Answered: Paul built a triangular garden in his…

Algebra: Structure And Method, Book 1

(REV)00th Edition

ISBN:9780395977224

Author:Richard G. Brown, Mary P. Dolciani, Robert H. Sorgenfrey, William L. Cole

Publisher:Richard G. Brown, Mary P. Dolciani, Robert H. Sorgenfrey, William L. Cole

Chapter5: Factoring Polynomials

Section5.13: Using Factoring To Solve Problems

Problem 12P

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Question

Paul built a triangular garden in his backyard, which is enclosed by a rectangular fence.
25 m
8 m
1
20 m
6 m
How much of the backyard is not covered by the garden?
452 m2
476 m2
524 m

548 m2

Expert Solution

Step 1

Given that,

The length of the rectangular fence is:

$L e n g t h = 25 m$

The width of the rectangular fence is:

$W i d t h = 20 m$

Since the area of the rectangle is given by:

$Area of rectangle=Length×Width$

Therefore,

The area of the rectangular fence is:

$A r e a o f r e c \tan g u l a r f e n c e = 25 m \times 20 m = 500 m^{2} . . . . . . (1)$

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