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Gene Interactions
When the expression of a single trait is influenced by two or more different non-allelic genes, it is termed as genetic interaction. According to Mendel's law of inheritance, each gene functions in its own way and does not depend on the function of another gene, i.e., a single gene controls each of seven characteristics considered, but the complex contribution of many different genes determine many traits of an organism.
Gene Expression
Gene expression is a process by which the instructions present in deoxyribonucleic acid (DNA) are converted into useful molecules such as proteins, and functional messenger ribonucleic (mRNA) molecules in the case of non-protein-coding genes.
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- You continue to study the expression of the hexose kinase gene and capture the following electron micrograph of the gene being expressed. MRNA 1 20 ORI 40 60 TTCGAGCTCTCGTCGTCGAGATACGCGATGATATTACTGGIAATATĞGGGATGCACTATC 5' 3' AAGCTCGAGAGCAGCAGCTCTATGCGCTACTATAATGACCA'NTATAÇCCCTACGTGATAG CACTATC promoter RNA polymerase ribosomeDNA: 5’-CTCTACTATAAACTCAATAGGTCC-3’ Draw a box around the sequence where RNA polymerase will bind to the DNA. What is this sequence called? Will transcription start at this sequence, to the left of this sequence (“upstream”) or, to the right of this sequence (“downstream”)? Draw a small arrow above the DNA strand where transcription will begin. Which DNA strand will RNA polymerase transcribe? Highlight this strand with your highlighter. (Hint: RNA pol is similar to DNA pol because it can only make new RNA in the 5’ to 3’ direction. Draw in an arrow to show the direction that RNA polymerase will move along the DNA strand.F. RNA TRANSCRIPTION AND GENE EXPRESSION 1. The template strand of a segment of double-helical DNA contains the sequence (5) СТТААСАССССТGAСТТСGCGCCGTCG (3') What is the base sequence of the mRNA that can be transcribed from this strand? b. What amino acid sequence could be coded by the mRNA in (a), starting from the 5' end? а.
- Part I. Structure-Function Relationships in Genes 1. Consider the "two-line model" of a gene shown below - each line represents one strand of a DNA double helix, and the transcription start site is indicated as +1. Use the two-line models provided when answering the following questions. 3' 5' +1 Assume that you know RNA polymerase will move to the right during transcription. On the diagram above, do the following: • Label "upstream" and "downstream" on this gene • Label where you would find the promoter min I • Draw a box where you would expect to find the TATA box • Draw a third line below the model representing the RNA transcript (label the ends!) • Label one of the DNA strands as the template strand 3' 2. Now, let's try that again! This time assume that you know RNA polymerase will move to the left during transcription. Repeat the same tasks as before on the diagram below: 5' 5' 3' +1 I I 5' 3'AGUC 24. Use the table below to answer the following question. The template strand of a gene contains this sequence: 3'-TAC TAG GCT AGT TGA-5'. A mutation occurs due to exposure to a chemical mutagen that changes the gene sequence to 3'-TAC TAG ACT AGT TGA-5'. How does this mutation affect the resulting amino acid sequence? (LS3-2) * Second mRNA base A UCU UGU Cys UGC UUU UAU Tyr UAC Phe UUC U UCC Ser UCA Phe Gly (G) Leu Glu (F) (L) UUA UAA Stop UGA Stop A Ser Asp (E) (D) Leu (S) UCG UUG UAG Stop UGG Trp Tyr (Y) Ala CUU CCU CAU CGU U (A) His C G U A CỤC Leu CUA CC Pro CCA CAC CGC Arg CGA Cys (C) G A Val CAA (V) Gln G Trp (W) CUG CCG CAG CGG G Arg (R) G А С A Leu AUU ACU AAU AGU (L) Asn Ser Ser (S) AUC Ile ACC Thr ACA AAC AGC C/ Lys (K) UGA AUA Pro AAA Lys AAG AGA Arg AGG Asn (N) (P) AUG Met or start ACG His Thr (T) Gin (H) (Q) GUU GCU GAU GGU lle Asp Arg (R) (1) GUC Val GUA GCC GAC GGC Ala GCA Gly GGA GAA Glu GAG GUG GCG GGG The mutation changes a single amino acid to another amino…pcc300ATAAADATATAOOTTAA 1. Use the genetic code table and the information in the diagram below to determine the amino acids that would make up the portion of the polypeptide shown. Include information for a key as well. DNA template 3' G CATA ACAGAGGATT-5' al bnsua AMAm pniwollot erfT E transcription s yd bnsita ebitgeqylog s sidmeaze of beae RNA strandUU UAOUOUU A-emoaodin 5'-CGUA AUUGUC UCCUUA- 3' J J JL erit o elinW (s) translation bluow terdt aspnso sigootiwsone polypeptide viemetis ns ebivo19 (d) ent ot etslanT Key:
- a. Use the genetic code provided in class to predict the sequence of protein formed from the following RNA strand. CGCUACAUCUUU b. If a gene mutation results in a frame shift, meaning the RNA sequence being read shifts rover by a base, and the translation machinery codes, instead, using the nucleotide sequence below, what is the amino acid sequence in the resulting portion of protein? GCUACAUCUUUA c. If a gene mutation results in a point mutation, meaning a single nucleotide is converted to a different nucleotide base, and the translation machinery codes, instead, using the nucleotide sequence below, what is the amino acid sequence in the resulting portion of protein? CGCUCCAUCUUU d. Which mutation is more likely to result in a slightly altered, but still functional, protein, the frame shift mutation or the point mutation? Briefly explain your answer.Q. Here is the sequence of a portion of a bacterial gene. The template strand is on the bottom: 5’-ATGCTGCGTGCATGGGATATAGGTAGCACACGTCC-3’ 3’-TACGACGCACGTACCC TATATCC ATCGTGTGCAGG-5’ (a) Assuming that transcription starts with the first C in the template strand, and continues to the end, what would be the sequence of the mRNA derived from this fragment? (b) Find the initiation and stop codons in this mRNA. (c) Would there be an effect on translation of changing the fourth T in the template strand to a C? If so, what effect? (d) Would there be an effect on translation of changing the fourth A in the template strand to a C? If so, what effect?Template strand: 5' AATCATAACTCATTG 3' A. Write the CODING strand of this sequence, including the 5' and 3' end designations. B. Write the amino acid sequence coded by this mRNA. The start codon is the first codon in the sequence that codes for Met. First position (5'-end) U < G บบบ UUC phe UUA UUG CUU Couleu CUC Coc CUA CUG AUU AUG AUC ile GUU GUC GUA GUG Second position C UCU UCC UCA UCG val CCU co CCC CCA 000 CCG ACU ACC ACC AUA ACA thr AUA ACA AUG met ACG GCU GCC ser GCA GCG pro ala UAU ORD tyr UAC UAA Stop UAG Stop CAU CAC CAA CAG - AAU AAC www AAA 10 asn AAG 7 his GAU GAC GAA GAG gin }| lys asp glu UGU UGC cys UGA Stop UGG trp CGU C00 CGC CGA 000 CGG AGU AGC ACA AGA AGG GGU GGC GGA GGG Initiation Termination arg ser arg gly DUAL SUAU DUAU DUAG Third position (3-end)
- Eukaryotic Genetic Sequence: 5'-TAC CAT GAT CCC TAT - 3' 1. What would be the newly synthesized DNA strand and explain how the strand will be replicated. Where in the cell would this occur? 2. What would be the synthesized mRNA strand, and how is it transcribed from the original DNA strand, and then converted from a pre-mRNA strand to a mature mRNA? Where in the cell does this occur? 3. What would be the anti-codons for the tRNA. What are the amino acids generated based on the RNA. How are these amino acids translated into protein and where in the cell does this happen?Open reading frames... correspond to introns, which are not read by the ribosome during translation correspond to contiguous fragments of DNA sequence that do not contain a stop codon when read in a particular frame correspond to contiguous fragments of DNA sequence that do not contain a stop codon when read in any of six frames are often rich in acetylated histones which allow transcription occur when fragments of DNA sequence are highly similar between two species are recognized by ribosomes to initiate translation10. A portion of 5'-AUGCCACGAGUUGAC-3'. What amino acid sequence does this code for? To answer the question please: I) explain what is the genetic code and list the properties of the genetic e 2) draw a diagram of protein synthesis; 3) determine which tRNA should be attached to the mRNA; 4) what is the anticodon for the very first tRNA that will attach to mRNA? mRNA molecule has the sequence an