Part (b). Follow the same procedure with P = 157 N. What is the friction force F needed to keep the block from slipping? If the friction force F for this case is in the same direction as that shown in the sketch, enter a positive number. If the friction force F for this case is in the opposite direction as that shown in the sketch, enter a negative value for F. What is the magnitude of the maximum friction force Fmax that can be produced in this situation (enter a positive value for Fmax)? mg F Answers: F = i N Fmax = i

Part (b). Follow the same procedure with P = 157 N. What is the friction force F needed to keep the block from slipping? If the friction force F for this case is in the same direction as that shown in the sketch, enter a positive number. If the friction force F for this case is in the opposite direction as that shown in the sketch, enter a negative value for F. What is the magnitude of the maximum friction force Fmax that can be produced in this situation (enter a positive value for Fmax)? mg F Answers: F = i N Fmax = i

Elements Of Electromagnetics

7th Edition

ISBN:9780190698614

Author:Sadiku, Matthew N. O.

Publisher:Sadiku, Matthew N. O.

ChapterMA: Math Assessment

Section: Chapter Questions

Problem 1.1MA

See similar textbooks

Similar questions

The 61-kg crate is stationary when the force Pis applied. Determine the resulting acceleration of the crate if (a) P = 0, (b) P = 128 N, and (c) P = 394 N. The acceleration is positive if up the slope, negative if down the slope. H, = 0.25 H = 0.19 61 kg 17° Part 1 Part (a). We need to decide if the block moves. The easy way to make this decision is to assume that the block does not move and then to test this assumption. If P = 0, what friction force Fis needed to keep the block from moving? mg F N Answer: F = i N
The 33-kg crate is stationary when the force Pis applied. Determine the resulting acceleration of the crate if (a) P-0, (b) P- 143 N, and (c) P- 322 N. The acceleration is positive if up the slope, negative if down the slope. [H, = 0.37 H = 0.29 33 kg Part 1 v Correct Part (a). We need to decide if the block moves. The easy way to make this decision is to assume that the block does not move and then to test this assumption. If P-0, what friction force Fis needed to keep the block from moving? mg Answer: F- 136.014 eTextbook and Media Hint Attempts: 2 of 3 used Part 2 Correct Part (a). P- 0. What is the maximum friction force Fmey that is availalbe for this situation? mg Answer: Fmax - 108.55
The 33-kg crate is stationary when the force Pis applied. Determine the resulting acceleration of the crate if (a) P- 0, (b) P- 143 N. and (c) P- 322 N. The acceleration is positive if up the slope, negative if down the slope. [H, = 0.37 H = 0.29 33 kg 25° Part 1 v Correct Part (a). We need to decide if the block moves. The easy way to make this decision is to assume that the block does not move and then to test this assumption. If P- 0, what friction force Fis needed to keep the block from moving? mg Answer: F- 136.014 N eTextbook and Media Hint Attempts: 2 of 3 used Part 2 v Correct Part (a). P- 0. What is the maximum friction force Fmey that is availalbe for this situation? mg N Answer: Fmax - 108.55 N
The 33-kg crate is stationary when the force Pis applied. Determine the resulting acceleration of the crate if (a) P = 0, (b) P = 143 N, and (c) P = 322 N. The acceleration is positive if up the slope, negative if down the slope. H, = 0.37 HE = 0.29 33 kg 25 Part 1 Part (a). We need to decide if the block moves. The easy way to make this decision is to assume that the block does not move and then to test this assumption. If P = 0, what friction force F is needed to keep the block from moving? mg P Answer: F = i N
The 83-lb crate is carefully placed with zero velocity on the incline. What is the acceleration of the block (positive down the incline) if (a) e = 13° and (b) e = 23°? u, = 0.35) 83 lb He = 0.30 Answers: (a) e = 13°, i ft/sec2 a = (b) e = 23°, a = ft/sec2
Determine the force P needed to (a) impend the crate to slide up the 150 -incline plane (b) give the crate an acceleration of 25 m/s? up the plane. 100 kg 20 H=0.30 = 0.20 15
The 65-kg crate is stationary when the force P is applied. Determine the resulting acceleration of the crate if (a) P = 0, (b) P = 223 N, and (c) P = 488 N. The acceleration is positive if up the slope, negative if down the slope. P Part 1 P 65 kg. Incorrect Part (o). We need to decide if the block moves. The easy way to make this decision is to assume that the block does not move and then to test this assumption. If P = 0, what friction force F is needed to keep the block from moving? 4₂ mg Answer: F = 1 260 [#₂ = 0.27 HA=0.20 N N
Р. The spring constant k = 700 N/m. The masses ma = 14 kg and mg = 18 kg. The horizontal bar is smooth. At the instant shown, the spring is unstretched and the mass B is moving downward at 1 m/s. How fast is B moving when it has moved downward 0.2 m from its present position? MA -0.3 m- wiww 0.15 m Note: Use conservation of Energy method
Determine the largest force P (to the nearest integer) which can be applied to the cord without causing motion. Blocks A and B have a mass of 8.5 kg and 11.5 kg, respectively. Úse a = 0.45 m, b = 0.55 m, µ (AB)= 0.3, µ (A) = 0.1, g = 9.81 m/s?. DO B. HAB A HA P (to the nearest integer) =
The 103-lb crate is carefully placed with zero velocity on the incline. What is the acceleration of the block (positive down the incline) if (a) = 11° and (b) 0 = 17°? H₂= 0.27 H&= 0.22 Answers: 103 lb (a) 0 = 11°, a = i (b) = 17°, a= i ! ft/sec² ft/sec²
Under the man's pushing force P = 37.3 lb, the uniform cabinet is sliding on the ground with a constant acceleration of a. If the uniform cabinet has weight of 150 lb, and the coefficient of kinetic friction between the cabinet and the ground is uk = 0.14, determine the normal force reaction under leg A. Please pay attention: the numbers may change since they are randomized. Your answer must include 2 places after the decimal point and proper unit. Take g = 32.2 ft/s2. -1 ft→+–1 ft-→| P 4 ft 3.5 ft A В Your Answer: Answer units
The 55-kg crate is stationary when the force P is applied. Determine the resulting acceleration of the crate if (a) P = 0, (b) P = 154 N, and (c) P = 362 N. The acceleration is positive if up the slope, negative if down the slope. 16 55 kg H₂=0.23 Hh=0.17