The shielding constant for He (1s)^2 is 0.31. Calculate the following: a) The energy of the 1s orbital for He (in J). b) The energy of the 1s orbital for He+ (in J). c) Draw the energy level diagrams through n = 3 for both He and He+. Discuss how the energy levels compare between the two species.
part c
The shielding constant for He (1s)^2 is 0.31.
Calculate the following:
a) The energy of the 1s orbital for He (in J).
b) The energy of the 1s orbital for He+ (in J).
c) Draw the energy level diagrams through n = 3 for both He and He+. Discuss how the energy levels compare between the two species.
In the presence of the inner electrons, the nuclear pull for the outer electrons is said to be less. This is due to the shielding of the outer electrons by the inner ones. This nuclear attraction is less than the actual nuclear charge.
This amount of nuclear attraction is measured by a constant called shielding constant as is given by the following expression:
Z* = Effective nuclear charge
Z = Atomic number
= Shielding constant
Trending now
This is a popular solution!
Step by step
Solved in 4 steps with 1 images
