P4 + 6H₂ →>> 4PH3 R = k[H₂] What is the rate constant for the reaction given the rate law and data? Trial [P]. (M) [H₂] (M) Initial Rate (M/s) 1 3.20 x 10-4 2 6.40 x 10-4 3 6.39 x 10-4 0.0220 0.0150 0.0220 0.0300 0.0440 0.0300 k = [?] Do not include units. Rate Constant Enter
P4 + 6H₂ →>> 4PH3 R = k[H₂] What is the rate constant for the reaction given the rate law and data? Trial [P]. (M) [H₂] (M) Initial Rate (M/s) 1 3.20 x 10-4 2 6.40 x 10-4 3 6.39 x 10-4 0.0220 0.0150 0.0220 0.0300 0.0440 0.0300 k = [?] Do not include units. Rate Constant Enter
Chemistry for Engineering Students
4th Edition
ISBN:9781337398909
Author:Lawrence S. Brown, Tom Holme
Publisher:Lawrence S. Brown, Tom Holme
Chapter11: Chemical Kinetics
Section: Chapter Questions
Problem 11.35PAE: 11.35 For the reaction 2 NO(g) + 2 H?(g) — N,(g) + 2 H,O(g) at 1100°C, the following data have been...
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P4+6H2–>4PH3 R=k[H2]
What is the rate constant for the reaction given the rate law and data?
![P4 + 6H₂
4PH,
What is the rate constant for the reaction
given the rate law and data?
Trial [P] (M) [H₂] (M) Initial Rate (M/s)
1
3.20 x 10-4
2
6.40 x 10-4
6.39 x 10-4
23
3
R =
R = k [H₂]
0.0220
0.0150
0.0220
0.0300
0.0440 0.0300
k = [?]
Do not include units.
Rate Constant
Enter](/v2/_next/image?url=https%3A%2F%2Fcontent.bartleby.com%2Fqna-images%2Fquestion%2F84192d13-4b9d-4fa2-9c27-58d0b79b0ddd%2F299ffa1f-2a2b-49e2-ac71-83e9e73e45ba%2Fnidrk0d_processed.jpeg&w=3840&q=75)
Transcribed Image Text:P4 + 6H₂
4PH,
What is the rate constant for the reaction
given the rate law and data?
Trial [P] (M) [H₂] (M) Initial Rate (M/s)
1
3.20 x 10-4
2
6.40 x 10-4
6.39 x 10-4
23
3
R =
R = k [H₂]
0.0220
0.0150
0.0220
0.0300
0.0440 0.0300
k = [?]
Do not include units.
Rate Constant
Enter
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