A 350 mm x 500 mm rectangular beamcarries a uniform dead load of 4.5 kN/m(including its own weight) and uniform liveload of 3 kN/m. If a concentrated live load P150 kN was added as shown in the figure,a) calculate the tension steel area requiredto support the loading. b) determine howmany 20 mm diameter rebar was needed. c)draw the cross-section of the reinforcedrectangular beam. P=150 KN500mmT350mm-

Solution:- Let, grade of steel is Fe=415, So fy=415 MPa Moment due to uniformly distributed load…

Answered: P=150 KN 500mm T350MMH

Engineering

Civil Engineering

P=150 KN 500mm T350MMH

Structural Analysis

6th Edition

ISBN:9781337630931

Author:KASSIMALI, Aslam.

Publisher:KASSIMALI, Aslam.

Chapter2: Loads On Structures

Section: Chapter Questions

Problem 1P

See similar textbooks

Similar questions

Light-grade steel channel was used as a purlin of a truss. The top chord of the truss is inclined I V: 4 H and distance between trusses is equal to 6 m. The purlin has a weight of 79 N/m and spaced at 1.2 m. on centers. The dead load including the roof materials is 720 Pa, live load of 1000 Pa and wind load of 1.2 1.2 1440 Pa. Coefficient of Purlins pressure at leeward and windward are 0.6 and 0.2 respectively. Assume all loads passes through the centroid of the section. Truss Properties of C 200 x 76 mm Sx = 6.19 x 104 mm Sy = 1.38 x 104 mm W = 79 N/m 12 12 1.2 I Allowable bending stress Fbx= Fby = 207 MPa Truss %3D 6m O Calculate the bending stress, fox, for dead load and live load combination (D+ L). Calculate the bending stress, foy, for dead load and live load combination (D + L). O Calculate the maximum ratio of actual to the allowable bending stress for load combination 0.75 (D + L + W) at the windward side. fbx = 151.14 MPa fby = 169.6 MPa Interaction = 1.25
Light-grade steel channel was used as a purlin of a truss. The top chord of the truss is inclined I V : 4 H and distance between trusses is equal to 6 m. The purlin has a weight of 79 N/m and spaced at 1.2 m. on centers. The dead load including the roof materials is 720 Pa, live load of 1000 Pa and wind load of 1.2 1.2 1440 Pa. Coefficient of Purlins pressure at leeward and windward are 0.6 and 0.2 respectively. Assume all loads passes through the centroid of the section. Properties of C 200 x 76 mm Sx = 6.19 x 104 mm Sy = 1.38 x 104 mm3 W = 79 N/m 1.2 Truss 1.2 12 12 1.2 Allowable bending stress Fbr = Fby = 207 MPa Truss %3D 6m O Calculate the bending stress, fox, for dead load and live load combination (D + L). Calculate the bending stress, foy, for dead load and live load combination (D + L). O Calculate the maximum ratio of actual to the allowable bending stress for load combination 0.75 (D + L + W) at the windward side. fbx = 151.14 MPa fby = 169.6 MPa Interaction = 1.25
Calculate the maximum tensile and compressive stresses in the section of BC of the beam. BLO Nara 0.5 in LOO KN 1.5 m ( 1.00 KN C 0.5 m D 200 inn 100 mm 25 mm 150 mm t T 25 mm
04. Analyze completely the compound truss loaded as shwon below. D 24 kN 3 m E 2 m F 3 @ 4 m 12 PROBLEM 4 TABLE OF ANSWERS: МЕМBER NUMBER FORCE (k) AB 1 CD 2 EF 3 BC CF 5 BF 6 DE 7 AD 8 AE 9 4.
University of Al-Qadisiyah- Civil Eng. Dept. Lecture 11; Shear design.mp4 Example 1 GIF the rectangular beam given in figure below has been designed for flexure; design the necessary shear reinforcement given that that beam is loaded by a uniformly distributed live load of 25 kN/m and a dead load (including self-weight) of 40 kN/m, take f. = 28 MPа, fyt 3 420 MPа, о 542 mm 600 mm 5020- +300 mm Face of Support 300 mm 7.0 m 44:רן •..
An 8 m long steel is simply supported at the left end and 2 m from the right end. It carries a total uniform load of 45 kN/m all throughout its length. STEEL DECIGON CIVIL ENGINEERING Beam properties: A= 11,500 mm² bf = 250 mm tw- 10 mm d === 350 mm If=: 16 mm 1x = 266 x 106 mm c) To strengthen the beam, 2- 200 mm x 10 mm cover plates, one at the top of the flange and the other at the bottom of the flange were added. What is the resulting maximum bending stress?
4-5 The A-36 steel rod is subjected to the loading shown. If the cross-sectional area of the rod is 60 mm², determine the displacement of B and A. Neglect the size of the cou- plings at B, C, and D. 60° 3.30 KN 2 kN D C B A 8 kN 60⁰ 3.30 KN 0.75 m 1.50 m 0.50 m 2 kN
Plate No.1: Structural Loads Calculation 1. The hollow core panel is made from plain stone concrete. Determine the dead weight of the panel. The holes each have a diameter of 100mm. 175 mm 300 mm 300 mm 300 mm/ 300 mm/ 2. The pre-cast T-beam has the cross-section shown. Determine its weight per foot of length if it is 3.6 m 300 mm/ made from reinforced stone concrete and eight 3/4-in. cold-formed steel reinforcing rods. 300 mm/ 8 in. 8 in. 20 in. -15 in. 15 in. 6 in. 6 in. 6 in.
A simply supported beam has a maximum moment equal to 20 KN.m. The beam has a width of 200 mm and a depth of 250 mm and is made up of 80% grade Narra. What is the actual bending stress of the beam in MPa? Blank 1 (use two decimal places, no need for unit)
2. A simple steel beam is to carry the concentrated loads as shown in the figure. (a) Drav the shear diagram, (b) determine the maximum moment, and (c) determine the wide-flange shape that should be used from the list shown if the allowable normal stress for the grade of steel to be used is 110 MPa 60 KN/m 60 KN/m A B 4 m 1m2 m Shape W310x129 S (cm') 1955 Shape W310x202 S (cm) 5049 3423 W310x143 2155 W310x226 W310x158 2565 W310x253 3853 W310x179 2675 W510x285 4311
H.W Draw S.f,B.M and elastic dliagrams for the beam Shown below by method of equntions ? 6W/m 20 KN 6m 2m 2m
TASK 3 250 180 14 I 30 24 Weld 450 A compound girder consists of a steel joist with steel plates welded onto each flange as shown. If the ends are simply supported and the effective span is 10 m, what is the maximum UDL which can be supported by the girder? [kN/m] Allowable longitudinal stress in plates = 110 MN/m² Allowable load in shear for each weld = 60 kN/m Allowable shearing stress in web of girder = 75 MN/m² Note: 1.0 MN/m² = 1.0 N/mm² 50