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- Mutations Can Uncouple chromosomal Sex from Phenotypic Sex Discuss whether the following individuals (1) have male or female gonads, (2) are phenotypically male or female (discuss Wolffian/Mllerian ducts and external genitalia), and (3) are sterile or fertile. a. XY, homozygous for a recessive mutation in the testosterone biosynthetic pathway, producing no testosterone b. XX, heterozygous for a dominant mutation in the testosterone biosynthetic pathway, which causes continuous production of testosterone c. XY, heterozygous for a recessive mutation in the MIH gene d. XY, homozygous fora recessive mutation in the SRY gene that abolishes functionMatch the chromosome disorder to its descriptionin the key. Jacobs syndrome a. female with undeveloped ovaries and uterus, unable to undergopuberty, normal intelligence, can live normally with hormonereplacementb. XXY male, can inherit more than two X chromosomesc. male or female, mentally impaired, short stature, flat face, stubbyfingers, large tongue, simian palm creased. XXX or XXXX femalee. caused by nondisjunction during spermatogenesis6. A man with X-linked colorblindness marries a woman with no history of ibba colorblindness in her family. The daughter of this couple marries a normal man noitenmot and ended up hone daughter, and their daughter also marries a normal man. This mont blast couple has already had a child with color blindness. do sri ni novig A) What is the chance that next child will be color blind? B) What is the chance that this last couple will have an affected daughter? (d #50x²50 (
- The maternal-effect mutation bicoid (bcd) is recessive. Inthe absence of the bicoid protein product, embryogenesis isnot completed. Consider a cross between a female heterozygousfor the bicoid mutation (bcd+/ bcd-) and a homozygousmale(bcd-/ bcd-). Predict the outcome (normal vs. failed embryogenesis) inthe F1 and F2 generations of the cross described.Name: 2. Some ladybugs have 10 black spots on their shells and some have 4. When true breeding 10 spot individuals are crossed with true breeding 4 spot individuals, the offspring have 7 spots. a. Propose two distinct explanations for this finding. Explain the nature of spot inheritance in each case. D. rew bacteria erred them figure above would of14N7 then ely 2 moldon omrod abitqaq ratlsmmem sge of delw toiisoibom s s neu not oomod aid to soubnup ogusl onomod odi to slevel ismon oouborg o o consu ud od souboini bluow uoy dairlw yd za00oq sdi mialex b. Propose an experiment that would distinguish between these possibilities. sor proieinsMatch the chromosome disorder to its descriptionin the key. Turner syndrome a. female with undeveloped ovaries and uterus, unable to undergopuberty, normal intelligence, can live normally with hormonereplacementb. XXY male, can inherit more than two X chromosomesc. male or female, mentally impaired, short stature, flat face, stubbyfingers, large tongue, simian palm creased. XXX or XXXX femalee. caused by nondisjunction during spermatogenesis
- Equalizing the Expression of X Chromosome Genes in Males and Females Males have only one X chromosome and therefore only one copy of all genes on the X chromosome. Each gene is directly expressed, thus providing the basis of hemizygosity in males. Females have two X chromosomes, but one is always inactivated. Therefore, females, like males, have only one functional copy of all the genes on the X chromosome. Again, each gene must be directly expressed. Why, then, are females not considered hemizygous, and why are they not afflicted with sex-linked recessive diseases as often as males are?5. A man who is not bald married a non bald female whose mother is bald. A. What is the chance that the couple will have a bald son? B. What is the probability that the couple will have a bald daughter? What is the chance that the couple will have a nonbald daughter? C.An attached-X female fly, XX ¬Y (see the “Insights and Solutions” box), expresses the recessive X-linked white-eye mutation. It is crossed to a male fly that expresses the X-linked recessive miniature-wing mutation. Determine the outcome of this cross in terms of sex, eye color, and wing size of the offspring.
- Barr bodies O are formed in females O are formed only in males cause an increased production of X-linked gene products O inactivate Xic on autosomes are formed only in males and inactivate Xic on autosomesThe maternal-effect mutation bicoid (bcd) is recessive. Inthe absence of the bicoid protein product, embryogenesis isnot completed. Consider a cross between a female heterozygousfor the bicoid mutation (bcd+/ bcd-) and a homozygousmale(bcd-/ bcd-). How is it possible for a male homozygous for the mutationto exist?. In humans, hemophilia is an X-linked recessive gene and will only be expressed in females if they are homozygous for this gene. However, in some rare cases, a heterozygote becomes hemophilic. Explain how this incident happens and why will there be skewed X-inactivation?
