Once an individual has been infected with a certain disease, let X represent the time (days) that elapses before the individual becomes infectious. An article proposes a Weibull distribution with a = 2.6, ß = 1.5, and y = 0.5. [Hint: The two-parameter Weibull distribution can be generalized by introducing a third parameter y, called a threshold or location parameter: replace x in the equation below, =x²-1-(x/B) α f(x; α, B) = Ba 0 x 20 x < 0 by x - y and x ≥ 0 by x ≥ y.] (a) Calculate P(1 < X < 2). (Round your answer to four decimal places.) 5763 standard deviation (b) Calculate P(X> 1.5). (Round your answer to four decimal places.) .7058 (c) What is the 90th percentile of the distribution? (Round your answer to three decimal places.) 2.567 days (d) What are the mean and standard deviation of X? (Round your answers to three decimal places.) mean x days days

Calculus For The Life Sciences
2nd Edition
ISBN:9780321964038
Author:GREENWELL, Raymond N., RITCHEY, Nathan P., Lial, Margaret L.
Publisher:GREENWELL, Raymond N., RITCHEY, Nathan P., Lial, Margaret L.
Chapter3: The Derivative
Section3.4: Definition Of The Derivative
Problem 50E
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please help me answer (d)

Once an individual has been infected with a certain disease, let X represent the time (days) that elapses before the individual becomes infectious. An article proposes a Weibull distribution
with a = 2.6, ß = 1.5, and y = 0.5. [Hint: The two-parameter Weibull distribution can be generalized by introducing a third parameter y, called a threshold or location parameter: replace x
in the equation below,
-{**
f(x; a, B) =
-1-(x/B)a
0
x ≥ 0
x < 0
by x - y and x ≥ 0 by x ≥ y.]
(a) Calculate P(1 < X < 2). (Round your answer to four decimal places.)
5763
(b) Calculate P(X> 1.5). (Round your answer to four decimal places.)
.7058
standard deviation
(c) What is the 90th percentile of the distribution? (Round your answer to three decimal places.)
2.567
days
(d) What are the mean and standard deviation of X? (Round your answers to three decimal places.)
mean
xdays
days
Transcribed Image Text:Once an individual has been infected with a certain disease, let X represent the time (days) that elapses before the individual becomes infectious. An article proposes a Weibull distribution with a = 2.6, ß = 1.5, and y = 0.5. [Hint: The two-parameter Weibull distribution can be generalized by introducing a third parameter y, called a threshold or location parameter: replace x in the equation below, -{** f(x; a, B) = -1-(x/B)a 0 x ≥ 0 x < 0 by x - y and x ≥ 0 by x ≥ y.] (a) Calculate P(1 < X < 2). (Round your answer to four decimal places.) 5763 (b) Calculate P(X> 1.5). (Round your answer to four decimal places.) .7058 standard deviation (c) What is the 90th percentile of the distribution? (Round your answer to three decimal places.) 2.567 days (d) What are the mean and standard deviation of X? (Round your answers to three decimal places.) mean xdays days
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