omputer Science Use only NumPy to create the Normalize Class: Image Normalization is a technique used to touch up images that are too dark or too light for the human viewing experience. Implement a version that outputs images with full dynamic range (0–255 pixel intensity). In other words, for each color channel (r, g, b), rescale the range of pixel values for that channel to include both 0 and 255. After normalizing, there should be at least one pixel with a red value of 0, at least one pixel with a red value of 255, at least one pixel with a green value of 0, etc. To normalize a list of numbers nums to the range 0–n, set nums[i] = (nums[i]−min(nums))/(max(nums)−min(nums))∗n for all i. Be careful! When max(nums) == min(nums), you should not touch that list (why?

omputer Science Use only NumPy to create the Normalize Class: Image Normalization is a technique used to touch up images that are too dark or too light for the human viewing experience. Implement a version that outputs images with full dynamic range (0–255 pixel intensity). In other words, for each color channel (r, g, b), rescale the range of pixel values for that channel to include both 0 and 255. After normalizing, there should be at least one pixel with a red value of 0, at least one pixel with a red value of 255, at least one pixel with a green value of 0, etc. To normalize a list of numbers nums to the range 0–n, set nums[i] = (nums[i]−min(nums))/(max(nums)−min(nums))∗n for all i. Be careful! When max(nums) == min(nums), you should not touch that list (why?

EBK JAVA PROGRAMMING

8th Edition

ISBN:9781305480537

Author:FARRELL

Publisher:FARRELL

Chapter16: Graphics

Section: Chapter Questions

Problem 17RQ

See similar textbooks

Similar questions

public class MyArrayList<E> { private int size; private E[] data; private int MAXELEMENTS = 100; public MyArrayList() { data = (E[])new Object[MAXELEMENTS]; size = 0; } public int getMAXELEMENTS(){ return MAXELEMENTS; } public boolean checkSpace() { if (size+1<MAXELEMENTS) return true; else return false; } public void add(int index, E e) { if (index < 0 || index > size) throw new IndexOutOfBoundsException ("Index: " + index + ", Size: " + size); for (int i = size - 1; i >= index; i--) data[i + 1] = data[i]; data[index] = e; size++; } public boolean contains(Object e) { for (int i = 0; i < size; i++) if (e.equals(data[i])) return true; return false; } public E get(int index) { if (index < 0 || index >= size) throw new…
Double any element's value that is less than controlValue. Ex: If controlValue = 10, then dataPoints = {2, 12, 9, 20} becomes {4, 12, 18, 20}. import java.util.Scanner; public class StudentScores { public static void main (String [] args) { Scanner scnr = new Scanner (System.in); final int NUM_POINTS = 4; int [] dataPoints new int [NUM_POINTS]; int controlValue; int i; controlValue = scnr. nextInt (); for (i = 0; i < dataPoints.length; ++i) { = scnr.nextInt (); dataPoints [i] } /* Your solution goes here * / for (i = 0; i < dataPoints.length; ++i) { System.out.print (dataPoints[i] + %3D " ") ; } System.out.println ();
Java Programming Class Car Attributes (all private): vin: String (5 digits) make: String model: String year: int price: double Methods: Parameterized constructor for initializing a new Car instance Getters for all attributes toString method to display a Car's attributes Executable Class Create an array of at least ten Car objects. Be sure to use many with identical last years and different prices. Create an ArrayList from the array. Shuffle the ArrayList. Sort the ArrayList first by year and then by price. See page 790-791. Using the forEach method and a lambda expression, print all cars sorted as above. Create a LinkedList from the ArrayList. Create an iterator capable of cycling both forward and backward through the LinkedList. Iterate forward through the entire LinkedList but without generating any output. Then iterate backwards through the LinkedList to print the cars data.
Main difference between an array and an ArrayList is that an ArrayList can store more data types an ArrayList can store more elements an ArrayList executes faster for retrieval and insertion an ArrayList takes care of the memory management automatically an ArrayList uses positions and an array uses indices
import java.util.ArrayList; public class Bus { privateStringname; privateintsize; privateintbasePrice; privateArrayList<Trip>approvedTrips; privateintlevel;// 1,2,3 for low,medium, high repectively; privateintid; privatestaticintnextId=0; privateMinistrymny; protectedStringtripTypes; privateintgetNextId(){ returnnextId++; } publicBus(){ approvedTrips=newArrayList<Trip>(); } publicBus(Stringname,intsize,intbasePrice,intlev,Ministrymny){ approvedTrips=newArrayList<Trip>(); this.name=name; this.size=size; this.basePrice=basePrice; this.level=lev; this.id=getNextId(); this.mny=mny; tripTypes="BASICTRANSPORT"; } publicbooleanavailable(Datedate){ booleanretval=true; for(Tript:approvedTrips) if(t.getDate().getDay()==date.getDay()) retval=false; returnretval; } publicintgetBasePrice(){ returnbasePrice; } publicintgetId(){ returnid; } publicStringgetName(){ returnname; } publicdoublegetSize(){ returnsize; } publicStringtoString(){ returnname; }…
2D-DP-3 int getLowestFromArray(int myList[], int size) int i; int lowestIndex = 0; for (i = 1; i myList[i]) lowestIndex = i; return lowestIndex; int main() int cData[2][5] = {{12, 5, 4, 7, 8}, {6, 35, 3, 27, 8}}; int i, lowest; for (i = 0; i < 2; i++) lowest = printf("%d\n", lowest); return 0; Given the code segment above, what will be needed to complete the code above? Assume the necessary libraries and functions are included and implemented. Encoding Instructions: Write your answers with NO SPACES. Answers not accepted by automatic checking in AnimoSpace due to not complying with the encoding instructions will not be given considerations.
Gradient FillIn this labwork are asked to write a GUI application again using AWT. This is a fairly easy labworkthat is more about getting used to synchronized online learning. You are expected to:• Draw two rectangles.• Both of them should be filled using GradientPaint() function of AWT. (Check out itsfunction definition that is listed below.)• The first gradient should be parallel to the diagonal of the first rectangle. The colorgradient should not be repeated (acyclic).• The second gradient should be horizontal. The color gradient should be repeated forthis one (cyclic).• You are free to choose the colors but other than that your output should be similar tothe example screenshot given below.
public class DynamicArray { private int array[]; private int count; private int size; public DynamicArray() { array = new int[1]; count = 0; size = 1; } public void add(int data) { if (count == size) { growSize(); // make array size double } array[count] = data; count++; } public void growSize() { int temp[] = null; if (count == size) { temp = new int[size * 2]; { for (int i = 0; i < size; i++) { temp[i] = array[i]; } } } array = temp; size = size * 2; } public void shrinkSize() { int temp[] = null; if (count > 0) { temp = new int[count]; for (int i = 0; i < count; i++) { temp[i] = array[i]; } size = count; array =…
Observer pattern The PhoneModel class stores a phone number as a list of digits, and the Keypad class has this method: public void simulateKeyPresses(int numKeyPresses)(0 that allows the user to enter digits one at a time then save each digit in the list. The Screen wants to respond to each key being entered. Make the model notify the observers whenever a new digit is entered for the phone number. The first observer prints the newest digit out to the screen The second observer prints "Now dialing 12345678901.." out to the screen (where the number is the number the model has). Only the Screen class can print to the screen The model must be decoupled from the Other classes.
public class CustomLinkedList { public static int findMax(IntNode headObj) { /* Type your code here */ } public static void main(String[] args) { IntNode headObj; IntNode currObj; IntNode lastObj; int i; int max; // Create head node headObj = new IntNode(-1); lastObj = headObj; // Add nodes to the list for (i = 0; i < 20; ++i) { currObj = new IntNode(i); lastObj.insertAfter(currObj); lastObj = currObj; } max = findMax(headObj); System.out.println(max); }}
public class StairViewer public static void main(String(] args) // Step 2: Create a rectangle and draw it as the // top step of the stair // location: (20, 10) // size: (20, 20) 18 // Step 3: Create a rectangle and draw it as the 19 // middle step of the stair 20 // location: below the top step, aligned on left // size: (40, 20) 21 22 23 24 // Step 4: Create a rectangle and draw it as the 25 // bottom step of the stair 26 // location: below the middle step, aligned on left // size: (60, 20) 27 28 29 30 } 31 32
dict1 = {(1,1,1):"red", (2,1,-1):"green", (0,-1,1):"red", (0,0,-2):"blue"}In this case, there are 2 red points, and their centroid is at ( (1+0)/2, (1-1)/2, (1+1)/2 ) = (0.5, 0, 1)Considering that in this example there is only one green and one blue point, they are representing the respective color's centroid. Hence, your function should return the following dictionary:{"red":(0.5,0.0,1.0), "green":(2.0,1.0,-1.0), "blue":(0.0,0.0,-2.0)}