Let's consider a rod having a solid circular cross-section with diameter of 4 mm and it is made of a material having a Young's modulus E = 120 Gpa and a Poisson's ratio of 0.33. If a tensile force F is subjected to that rod cross-section, the diameter becomes 3.995 mm. determine the applied force F. Select one: O F= 2856 N OF = 2285 N OF = 7140N OF = 5712 N OF = 3427 N O F = 8568 N Let's consider a rod having a solid circular cross-section with diameter of 4 mm and it is made of a material having a Young's modulus E =120 Gpa and a Poisson's ratio of 0.33. If a tensile force F is subjected to that rod cross-section, the diameter becomes 3.995 mm. determinethe applied force F.Select one:O F = 2856 NO F = 2285 NOF = 7140 NO F = 5712 NO F = 3427 NO F = 8568 N

Calculate linear strain with the given data

Answered: OF = 5712 N

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OF = 5712 N

Mechanics of Materials (MindTap Course List)

9th Edition

ISBN:9781337093347

Author:Barry J. Goodno, James M. Gere

Publisher:Barry J. Goodno, James M. Gere

Chapter2: Axially Loaded Members

Section: Chapter Questions

Problem 2.3.21P: A slightly tapered bar AB of solid circular crass section and length L is supported at end B and...

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Concept explainers

Axial Load

When a bar of the uniform cross-section is acted by a load, such that the load acts along the longitudinal axis of the bar, such kinds of loadings are known as axial loadings. In general terms, a load is an external force acting on a component. An axial load acts perpendicular to the geometric cross-section of the component. Based on the direction of the application of the load, an axial load can be tensile or compressive. The analysis of bodies under the action of axial loads is generally studied under the branch of mechanics, known as statics.

Question

Let's consider a rod having a solid circular cross-section with diameter of 4 mm and it is made of a material having a Young's modulus E = 120 Gpa and a Poisson's ratio of 0.33. If a tensile force F is subjected to that rod cross-section, the diameter becomes 3.995 mm. determine the applied force F. Select one: O F= 2856 N OF = 2285 N OF = 7140N OF = 5712 N OF = 3427 N O F = 8568 N

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