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- Would you kindly answer this question A rolling operation on a 250 mm wide, 8 mm thick, 1112 cold rolled steel takes place using hardened steel rolls with a surface finish of 0.03 μm. The rolls have a diameter of 350 mm and rotates at 115 rpm. The final thickness of the plate is 6 mm and the entry speed of the plate is 1.8 m/s. Calculate: 3.1 The minimum coefficient of friction required, that will make the rolling operation possible. 3.2 The required roll force. 3.3 The position of the neutral point, ?? 3.4 Indicate, using a sketch, the neutral point showing all relevant notation and dimensions.A 200 mm wide and 42.0 mm thick plate made of low carbon steel is to be reduced in one pass in a rolling operation. As the thickness is reduced, the plate widens by 4%. The entrance speed of the plate is 15.0 m/min. The roll radius is 325 mm and the rotational speed is 49.0 rev/min. i. If the current horsepower of the available rolling machine is 950 HP, how much thickness could the machine reduce the plate thickness to? ii. If the required thickness needs to be 34.0mm, how could the original width of the plate be changed in order to use the same machine?Question 7 A component is designed to be hot forged in an impression die. The projected area of the product is 5800 mm?. During the forging process flashing is formed so that the area including the flash will be 8900 mm?. The part geometry is considered to be simple and the heated work material yields at 92 MPa. Calculate the maximum force required to perform the operation. 7.1 7.2 What are the advantages and disadvantages to forge a product through the open forging process, rather than to machine it from the same material?
- Question 3A rolling operation on a 250 mm wide, 8 mm thick, 1112 cold rolled steel takes place using hardened steel rolls with a surface finish of 0.03 μm. The rolls have a diameter of 350 mm and rotates at 115 rpm. The final thickness of the plate is 6 mm and the entry speed of the plate is 1.8m/s Calculate: 3.1)The minimum coefficient of friction required, that will make the rolling operation possible. 3.2 The required roll force. 3.3 The position of the neutral point, ??3.4 Indicate, using a sketch, the neutral point showing all relevant notation and dimensionsA hot rolling operation is being carried out on 250 mm wide and 25mm thick low carbon steel (C=165MPA, m=0.10) plate at 1000°C. The roll diameter is 450mm and it is rotating at 120 proposed that a reduction of 20% be taken in the rolling process. rpm. It is If the strain rate in the rolling processes can be expressed by the following expression: V, h. = 3 L h, Where V, is the roll surface speed, ho is the intial thickness of the plate, hfis the final thickness of the plate and L is the contact length between the roll and plate in the deformation zone. Compute the flow stress required to deform the carbon steel plate.1. A component is designed to be hot forged in an impression die. The projected area of the product is 5800 mm2. During the forging process flashing is formed so that the area including the flash will be 8900 mm2. The part geometry is considered to be simple and the heated work material yields at 92 MPa. Calculate the maximum force required to perform the operation. 2. What are the advantages and disadvantages to forge a product through the open forging process, rather than to machine it from the same material?
- An open die forging operation is performed to produce a steel cylinder with a diameter of 9.7mm and a height of 1.7mm. The strength coefficient for this steel is 500MPA, and the strain hardening exponent is 0.25. Coefficient of friction at the die-work interface is 0.12. The initial stock of raw material has a diameter of 5mm. (a) What height/length of stock is needed to provide sufficient volume of material for this forging operation? (b) Compute the maximum force that the punch must apply to form the head in this open- die operation.5) A steel specimen of rectangular cross section with 120 mm width, 180 mm thickness and 90 mm height was upset at room temperature by open-die forging to a height of 55 mm. If the strength coefficient and strain hardening exponent of this material were 1015 MPa and 0.17 respectively, the coefficient of friction is 0.2, and assuming that the thickness would not change during forging; determine the required upsetting force at the end of stroke.(c) A flat rolling operation is being carried out where the roll radius is 200 mm and the roll rotates at 100 rpm. The workpiece material is annealed low carbon steel with 200 mm wide and 10 mm thickness. The strength coefficient and the strain hardening of the carbon steel are 530 MPa and 0.26, respectively. The coefficient of friction is 0.2. (i) Caicurae tne roll force and torque if the workpiece is rolled to a thickness of 4 mm. (ii) Calculate the maximum possible draft and evaluate how friction effect the thickness of the rolled workpiece.
- Estimate the power for annealed low carbon steel strip 200 mm wide and 10 mm thlck, rolled to a thickness of 6 mm The roll radius is 200 mm), and the roll rotates at 200 rev/min; use coefficient 0f friction at the die-work interface (p)= 0.1, Alow carbon steel such as AlSI 1020 has K (strength coefficient) = 530 MPaand n (stram hardening exponent) = 0.26An austenitic stainless steel plate with a width of 100 mm, a length of 150 mm and a thickness of 50 mm is to be hot forged in a hydraulic press so that the width remains constant. If it is to be reduced in one step to a thickness of 40 mm, calculatea) the actual load that needs to be applied at the end of the forging, as well as b) the corresponding deformation energy. In previous plane strain compression tests, it was found that the material exhibits an average plane strain yield stress of 80 MPa at the forging temperature. Assume that the efficiency of the process is 0.6 Answer: Pfr= 2.5 MN ; WTr= 25 kJEstimate the power for annealed low carbon steel strip 200 mm wide and 10 mm thick, rolled to a thickness of 6 mm. The roll radius is 200 mm, and the roll rotates at 200 rev/min; use coefficient of friction at the die-work interface (p)=0.1. A low carbon steel such as AISI 1020 has K (strength coefficient) = 530 MPa and n ( strain hardening exponent) =0.26a)1059 kWb)950 kWc)1183 kWd)875 kW