Now the pilot activates the burner for 10 seconds. This action affects the temperature in a 12-foot- wide column 20 feet high, directly above the burner. A cross section of the balloon depicting this column in shown in the following figure. 20 ft ΖΑ 44 ft 28 ft 12 ft | Figure 5.63 Activating the burner heats the air in a 20-foot-high, 12- foot-wide column directly above the burner. Assume that after the pilot activates the burner for 10 seconds, the temperature of the air in the column described above increases according to the formula H(r,0,2) -2:- 48. Then the temperature of the air in the column is given by T₁(1,0,2)= 2-r 10 +210+(-2-48), while the temperature in the remainder of the balloon is still given by 2-r To(7,0,2)= +210. 10 3. Find the average temperature of the air in the balloon after the pilot has activated the burner for 10 seconds.

Algebra & Trigonometry with Analytic Geometry
13th Edition
ISBN:9781133382119
Author:Swokowski
Publisher:Swokowski
Chapter7: Analytic Trigonometry
Section7.6: The Inverse Trigonometric Functions
Problem 74E
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I calculated the temperature before the start of the burner to be 209.9 but not sure how to get the temperature after the 10s

Now the pilot activates the burner for 10 seconds. This action affects the temperature in a 12-foot-
wide column 20 feet high, directly above the burner. A cross section of the balloon depicting this
column in shown in the following figure.
20 ft
ΖΑ
44 ft
28 ft
12 ft
|
Figure 5.63 Activating the burner heats the air in a 20-foot-high, 12-
foot-wide column directly above the burner.
Assume that after the pilot activates the burner for 10 seconds, the temperature of the air in the
column described above increases according to the formula
H(r,0,2) -2:- 48.
Then the temperature of the air in the column is given by
T₁(1,0,2)=
2-r
10
+210+(-2-48),
while the temperature in the remainder of the balloon is still given by
2-r
To(7,0,2)=
+210.
10
3. Find the average temperature of the air in the balloon after the pilot has activated the burner for 10
seconds.
Transcribed Image Text:Now the pilot activates the burner for 10 seconds. This action affects the temperature in a 12-foot- wide column 20 feet high, directly above the burner. A cross section of the balloon depicting this column in shown in the following figure. 20 ft ΖΑ 44 ft 28 ft 12 ft | Figure 5.63 Activating the burner heats the air in a 20-foot-high, 12- foot-wide column directly above the burner. Assume that after the pilot activates the burner for 10 seconds, the temperature of the air in the column described above increases according to the formula H(r,0,2) -2:- 48. Then the temperature of the air in the column is given by T₁(1,0,2)= 2-r 10 +210+(-2-48), while the temperature in the remainder of the balloon is still given by 2-r To(7,0,2)= +210. 10 3. Find the average temperature of the air in the balloon after the pilot has activated the burner for 10 seconds.
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