(no) 8. A manx mouse with blue fur is crossed to a long-tailed, black mouse heterozygous for color. If tail length shows incomplete dominance and blue fur is a recessive trait, what is the probability of getting blue mice with intermediate tail length? (note: genes for color and tail length travel on separate chromosomes)

(no) 8. A manx mouse with blue fur is crossed to a long-tailed, black mouse heterozygous for color. If tail length shows incomplete dominance and blue fur is a recessive trait, what is the probability of getting blue mice with intermediate tail length? (note: genes for color and tail length travel on separate chromosomes)

Name: Urgent (ne)8. A manx mouse with blue fur is crossed to a long-tailed,
Uploaded: 2024-03-20T06:43:04.000Z
Channel: Bartleby
Description: Urgent (ne)8. A manx mouse with blue fur is crossed to a long-tailed, black mouse heterozygous for color. If taillength shows incomplete dominance and blue fur is a recessive trait, what is the probability of gettingblue mice with intermediate tail l

Biology: The Dynamic Science (MindTap Course List)

4th Edition

ISBN:9781305389892

Author:Peter J. Russell, Paul E. Hertz, Beverly McMillan

Publisher:Peter J. Russell, Paul E. Hertz, Beverly McMillan

Chapter12: Mendel, Genes, And Inheritance

Section: Chapter Questions

Problem 7TYK: In cats, the genotype AA produces tabby fur color; Aa is also a tabby, and aa is black. Another gene...

See similar textbooks

Similar questions

7) In cats, the gene for coat color is both X-linked and incompletely dominant. There are black coat and yellow coat alleles, with calico (tortoise shell) as the heterozygous form. If a yellow male mates with a calico female, what are the expected offspring phenotypes (in percent)? hbit
в IUA Callbri 12 3 4 12. In Drosophila, gray body color is dominant over ebony body color, while long wings are dominant over vestigial wings. Work the following crosses through the F2 generation, and determine the genotypic and phenotypic ratios for each generation. Assume that the P1 individuals are homozygous. a. Gray, long x ebony, vestigial b. Gray, long x gray, vestigial !! !! lili 田

EXAMPLE PROBLEM Two black female mice are crossed with a brown male. In several litters, female I produced 9 black offspring and 7 brown; female II produced 57 black offspring. What deductions can you make about the inheritance of black and brown coat color in mice? What are the genotypes of the parents? Dominance and recessive describe which of two possible phenotypes are exhibited when two different alleles occur in the same individual.
Another gene in Drosophila determines wing length. The dominant wild-type allele of this gene produces long wings; a recessive allele produces vestigial (short) wings. A female that is true- breeding for red eyes and long wings is mated with a male that has purple eyes and vestigial wings. F1 females are then crossed with purple-eyed, vestigial-winged males. From this second cross, a total of 600 offspring are obtained with the following combinations of traits: 252 with red eyes and long wings 276 with purple eyes and vestigial wings 42 with red eyes and vestigial wings 30 with purple eyes and long wings Are the genes linked, unlinked, or sex-linked? If they are linked, how many map units separate them on the chromosome?
In cats, the genotype AA produces tabby fur color; Aa is also a tabby, and aa is black. Another gene at a different locus is epistatic to the gene for fur color. When present in its dominant W form (WW or Ww), this gene blocks the formation of fur color and all the offspring are white; ww individuals develop normal fur color. What fur colors, and in what proportions, would you expect from the cross AaWw Aa Ww?
2. In Drosophila, gray body color is dominant to ebony body color, while long wings are dominant to vestigial wings. Assuming that the F1 individuals are homozygous, work the following crosses through the F2 generation, and determine the genotypic and phenotypic ratios for each generation. (a) gray, long × ebony, vestigial
Part 2 Spotty and Cutie have puppies and 50% of the puppies are unaffected for both traits (not blind and not BHFD). What is Spotty's genotype? bbDD bbdd BBDd BbDd BbDD BBdd
3) Short tail length in cattle is caused by an X-linked recessive allele. Roan coat colour of cattle is due to co-dominance (other coat colours are red and white). a) Show the results of a cross between a bull which has a roan coat and a short tail and a white cow which is heterozygous long tail. b) What percentage of male calves will have a red coat and a short tail?
In Labrador retrievers, two genes determine fur color: the E gene and the B gene. Black fur (B) is dominant to brown fur (b). However, the presence of (ee) will overshadow and create a puppy with yellow fur. Create a Punnett square crossing 2 Labs that are heterozygous for both genes. What are the resulting phenotypes? Don’t forget to take epistasis into account!
3. Short-tailed pup distribution. In mice, the dominant T allele results in a short tail. Homozygous T/T genotype is lethal, which means mouse embryos with this genotype die before they are born. Homozygous t/t is normal, with normal tail. A cross between two short-tailed mice produces a litter of 5 pups. a). What are the genotype(s) of the two short-tailed mice used in the cross? b). What are the possible genotypes and phenotypes of the 5 pups? What are their perspective ratio?
In domesticated cats, the following are Independently assorting: 6. Normal ears (T) is dominant to tufted ears (t); Curved whiskers (C) is dominant to straight whiskers (c); The presence of six toes (S) is dominant to five toes (s); Gene for hair length is an X-linked codominant. The three phenotypes for hair length are long (XHXH), medium (X"X*), and short (X"Xh); medium is the heterozygous condition. Given two parents: TtccSSXHXh x TtCcSsXHY a) How many different gametes could be formed in the female cat with respect to these four traits? b) How many different phenotypes are possible in the offspring from this mating?
5A. In shorthorn cattle, the polled condition is dominant over horned. Also, the heterozygous condition (RW) of red coat (R) and white coat (W) is roan, an example of codominance. (The roan coat contains both red and white fur because neither allele is dominant over the other). If a homozygous polled, white male is bred to a horned, red female, what will be the appearance of the F1 generation? Horned: r: Roan Coat: a. Possible genotypes for Polled condition Coat:_ ossible geno c. Male genotype: d. Female genotype: Male possible gametes Female possible gametes e. f. Genotypic Ratio: g. Phenotypic Ratio 5B, Breed two of the F1 generation to determine the possibilities in the F2 generation. Horned: a. Possible genotypes for Polled condition b. Possible genotypes for Red coat: White Coat:_ Roan Coat: c. Male genotype: d. Female genotype Male possible gametes Female possible gametes: f. Genotypic Ratio: g. Phenotypic Ratio