N2(g) + 3H2(g) = 2NH3 (g) For the given reaction, the equilibrium concentrations were observed as [NH3] = 3.1 x 102 mol/L, [N2] = 8.5 x 10 mol/L, [H2] = 3.1 x 10-3 mol/L at 127 C. a) Calculate the value of K at 127°C for this reaction. b) Calculate the value of K at 127 C for the following reaction: 2NH3 (g) = N2(g) +3H2g) c) Calculate the value of K at 127°C for the following reaction: 1/2 N2(g) + 3/2 H2(g) = NH3 (g)

Chemistry & Chemical Reactivity
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Chapter15: Principles Of Chemical Reactivity: Equilibria
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N2(g) + 3H2(g) = 2NH3 (g)
For the given reaction, the equilibrium concentrations were observed as [NH3] = 3.1 x 10²
mol/L, [N2] = 8.5 x 10-' mol/L, [H2] = 3.1 x 10³ mol/L at 127 C.
a) Calculate the value of K at 127°C for this reaction.
b) Calculate the value of K at 127°C for the following reaction: 2NH3 (g) = N2(g) + 3H2(g)
c) Calculate the value of K at 127 C for the following reaction:
1/2 N2(g) + 3/2 H2(g) = NH3 (g)
Transcribed Image Text:N2(g) + 3H2(g) = 2NH3 (g) For the given reaction, the equilibrium concentrations were observed as [NH3] = 3.1 x 10² mol/L, [N2] = 8.5 x 10-' mol/L, [H2] = 3.1 x 10³ mol/L at 127 C. a) Calculate the value of K at 127°C for this reaction. b) Calculate the value of K at 127°C for the following reaction: 2NH3 (g) = N2(g) + 3H2(g) c) Calculate the value of K at 127 C for the following reaction: 1/2 N2(g) + 3/2 H2(g) = NH3 (g)
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