n sorted numbers. def binary_search(data, value): n = len(data) left = 0 right = n - 1 while left <= right: middle = (left + right) // 2 if value < data[middle]: right = middle - 1 elif value > data[middle]: left = middle + 1 else: return middle return 'Value is not in the list' print(binary_search(data,
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1.2
What is the complexity of the following Python code snippet in Big- O notation? Assume the input is a list of n sorted numbers.
def binary_search(data, value):
n = len(data)
left = 0
right = n - 1
while left <= right:
middle = (left + right) // 2
if value < data[middle]:
right = middle - 1
elif value > data[middle]:
left = middle + 1
else:
return middle
return 'Value is not in the list'
print(binary_search(data, 2021))
Step by step
Solved in 2 steps with 1 images
- 4 20 matrix can be represented as a list and a column count value in Python. For example, the 3x3 matrix 1 2 3 45 6 7 8 9 can be row-wise represented as ([1,2,3,4,5,6,7,8,9], 3), where the number3 represents the number of columns in the matrix. Similarly, 1 35 24 6 becomes ([1,3,5,2,4,6], 3). A submatrix can be defined as an (1,r,t,b) tuple, where 1 and r are left and right column indices, and t and b are top and bottom row indices (all inclusive). write a function that takes a tuple containing the list representing a matrix, and the column count of the matrix, along with another tuple representing a specific submatrix, and returns the list representation of the submatrix along with its column count as a tuple. For example, given submatrix(([1,2,3,4,5,6,7,8,9,10,11,12], 4), (1,2,0,1)) returns: ([2,3,6, 7], 2) because, ([1, 2,3,4,5,6,7,8,9,10,11,12], 4) represents: 2 3 4 5 6 7 9 10 11 12 8 and (1,2,0,1) represents the submatrix bet ween column indices 1 and 2 (both inclusive), and row…Write a C++ program to find the number of comparisons using binarySearch and the sequintial search algorithm as follows:Suppose list is an array of 1000 elements.1.1 Use a random number generator to fill list.1.2 Use any sorting algorithm to sort the list.1.3 Search list for some items as follows:a. Use the binary search algorithm to searcg the list. (You may need to modify the algorithm to count the number of comparisons.b. Use the binary search algorithm to search the list, switching to a sequentialsearch when the size of the search list reduces to less than 15. (Use the sequential search algorithm for a sorted list.)Print the number of comparisons for Questions 1.3a and b. If the item is found in the list, then print its position.Define a python function that is passed a table (2D list of lists) of integers and returns the total of all the integers in the table. def total(T): """" Returns the sum of all the elements in the integer table T"""
- #include<bits/stdc++.h> using namespace std; void bubbleSort(int arr[], int n) { for (int i = 0; i < n - 1; i++) { for (int j = 0; j < n - i - 1; j++) { if (arr[j] > arr[j + 1]) { int temp = arr[j]; arr[j] = arr[j + 1]; arr[j + 1] = temp; } } } } int binarySearch(int arr[], int l, int r, int x, int& comp) { comp++; if (r >= l) { int mid = l + (r - l) / 2; if (arr[mid] == x) { return mid; } if (arr[mid] > x) { return binarySearch(arr, l, mid - 1, x, comp); } return binarySearch(arr, mid + 1, r, x, comp); } return -1; } int main() { int Num[8192]; srand(time(NULL)); for (int i = 0; i < 8192; i++) { Num[i] = rand() % 10001; } clock_t starting_time = clock(); bubbleSort(Num, 8192); clock_t ending_time = clock(); clock_t result =…Java: Write a program to find the number of comparison using sequentialSearch and binarySearch algorithms as follows: Suppose list is an array of 1200 elements. Use a random number generator to fill list; Use a sorting algorithm to sort list; Search list for some items as follows: a. Use the binary search algorithm to search list (please work on SearchSortAlgorithms.java and modify the algorithm to count the number of comparisons) b. Use the sequential search algorithm to search list (please work on SearchSortAlgorithms.java and modify the algorithm to count the number of comparisons) Print the number of comparison in step 3(a) and 3(b). If the item is found in the list, print its position.Code: #include <bits/stdc++.h> using namespace std; void BUBBLE(int A[],int N){ for(int k=0;k<N-1;++k){ for(int ptr=0;ptr<N-k-1;++ptr){ if(A[ptr]>A[ptr+1]){ int temp = A[ptr]; A[ptr] = A[ptr+1]; A[ptr+1]=temp; } } }} //function to print the arrayvoid printArray(int arr[],int n){ int i; for(i=0;i<n;i++) cout<<arr[i]<<" "; cout<<endl;} //driver function to test the modulesint main(){ int arr[] ={15,17,5,3,25,66,14,7,59,100}; int n=sizeof(arr)/sizeof(arr[0]); cout<<"\nOriginal array: "; printArray(arr,n); cout<<"\n\nOutput of Bubble sort are shown below:\n"; BUBBLE(arr,n); printArray(arr, n); return 0;} Q: Remove the Function from the above code
- Python Numpy function to complete: def t19(N, s, X, y): Inputs: N: An integer s: A floating-point number - x: A floating-point number - y: A floating-point number Returns: A numpy array I of shape (N, N) such that I[i, j] exp(-||(j, i) –- (x, y)||^2 / s^2) Par: 3 lines Instructor: 2 lines return Noneusing namespace std; int main() int i, m=0,n=4; float arr[100] (55,66,88,1); for(i=0; i11 - The code segment below has time complexity? for (int i=0; iA-1D-9 Given the code segment below, what will be the sum of ALL elements of dCData after running the codes? Limit your answer to one (1) decimal place only if answer is a floating point number. int main() int i; double dAData[3] = {1.e, 2.0, 3.0}; double dBData[3] = {4.e, 5.0, 6.0}; double dCData[3]; for (i = e; i < 3; i++) dCData[i] = dAData[i] + dBData[2-i] +i * i; return e; Assume the necessary libraries and functions are included and implemented. Write INVALID (in all CAPITAL LETTERS) if it is an invalid access, or if the task will cause a syntax or logical error.def find_root4(x, epsilon): ''' IN PYTHON Assume: x, epsilon are floating point numbers and epsilon > 0 Use bisection search to find the following root of x such that If x >=0, return y such that x - epsilon <= y ** 2 <= x + epsilon Else, return y such that x - epsilon <= y ** 7 <= x + epsilon Note: You must use bisection search to implement the function. ''' pass10. Consider the following program, implementing binary search to look for a word in a list of words: Here we're looking for the string target, in the list list_of_words. def search_binary(list_of_words, target, debug_print-False): "*" Find and return an index of target in list_of_words # 1 and r represent the region of interest that we search over. # initially this is the whole of xs 1- 0 r = len(list_of_words) while 1 list_of_words[m][0]: 1 - m+1 else: assert target == list of_words[m][@] return list_of_words[m][1] return -1 What has to be true about list of_words in order for this function to find the index of the target word? You might want to look at Lecture 17 for reference if this seems mysterious. Is this search function fast? Can you explain why?SEE MORE QUESTIONSRecommended textbooks for youDatabase System ConceptsComputer ScienceISBN:9780078022159Author:Abraham Silberschatz Professor, Henry F. Korth, S. SudarshanPublisher:McGraw-Hill Education
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