n processes are time-sharing the CPU using RR scheduling, each requiring T ms of CPU time to complete. needs to show your work (a) How long will the execution take on a machine with n CPUs? (b) How long will the execution take on a single CPU machine when the context switch overhead is zero? (c) How long will the execution take on a single CPU machine when: • the length of the time quantum is Q ms • the time to perform each context switch is S ms (d) Repeat the previous calculation using n=5, T-10,000, Q=100, S=10.

n processes are time-sharing the CPU using RR scheduling, each requiring T ms of CPU time to complete. needs to show your work (a) How long will the execution take on a machine with n CPUs? (b) How long will the execution take on a single CPU machine when the context switch overhead is zero? (c) How long will the execution take on a single CPU machine when: • the length of the time quantum is Q ms • the time to perform each context switch is S ms (d) Repeat the previous calculation using n=5, T-10,000, Q=100, S=10.

Database System Concepts

7th Edition

ISBN:9780078022159

Author:Abraham Silberschatz Professor, Henry F. Korth, S. Sudarshan

Publisher:Abraham Silberschatz Professor, Henry F. Korth, S. Sudarshan

Chapter1: Introduction

Section: Chapter Questions

Problem 1PE

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Multiprocessor systems use multiple CPUS to perform various tasks. This increases throughput and reduces response time. In this problem, a multiprocessor system has a certain number of processors. Each processor has the ability to schedule a limited number of processes in one second. However, after this scheduling, the processor's ability is reduced to floor(ability/2). Given the processor's abilities and the number of processes, what is the minimum time required to schedule all the processes in the system? Example n = 5 (number of processors and size of ability[]) ability = [3, 1, 7, 2, 4] processes = 15 This optimal solution is: 1. First, the processor with ability = 7 schedules 7 processes in one second. Now, ability = [3, 1, 3, 2, 4] because 7 was reduced to floor(7/2). There are 15 - 7 = 8 remaining processes. 2. Second, the processor with ability = 4 is used. After that, ability = [3, 1, 3, 2, 2]. Remaining processes = 8 - 4 = 4. 3. Third, a processor with ability = 3 is used.…
On a single CPU system, we have 2 processes running concurrently, with the same I/0 percentage = in the average case, best case, worst case? 60%. What are the CPU Utilizations
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