myBytes BYTE 12h,34h,56h,78h
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Find the register values:
.data
myBytes BYTE 12h,34h,56h,78h
.code
mov ax,WORD PTR [myBytes] ; AX = ?
mov ax,WORD PTR [myBytes+2] ; AX = ?
mov eax,DWORD PTR myBytes ; EAX = ?
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- variable1 DWORD 14253647h Assuming that the computer uses little endian order, illustrate how 'variable1' is stored in the memory. Answer format: For the following example, variable1 D WORD 14253647h If you think 14 goes to 0-th byte and 25 goes to 1st byte, you can write answer as follows: Offset (i-th byte) : value 0:14 1:25 Paragraph B III#include Servo Main Servo int trigpin = echo pin = 8) opm distance i i Note This Code for Smart Ductoin using Arduino, Sensor & Motor → please give Suplanation about this code int float durahimn float cm Void Setup() Servo Main, allach (7) i Pin Mode (trigpin, output) i Pin Mode (echopin, imput); f void loop() digital write (trigping low) i delay (2); digital write (trigpin, High) ; delay Microsecond (10): digital write / trigpin, low) i duration= Pulse cm = (duration / 5882); distance = Cmi. if (distance (30) { Servo Main write (180), delay (3000) i f else & Servo Mam write (o); delay (50); f In (echopin, High) iWhat are the benefits and drawbacks of using decimal data types?
- T2 read_item (X); read_item (Y); Z = Y - X write_item (Z); T1 read_item (X); read_item (Y); Y = Y + X write_item (Y); Suppose: TS(T1) = 3 TS(T2) Using Basic Timestamp Ordering to show the execute T1 and T2bit_flag.c #include <stdio.h> #include <stdlib.h> #include "bit_flags.h" typedef struct bit_flags { int size; int capacity; int *bit; } Bit_flags; BIT_FLAGS bit_flags_init_number_of_bits(int number_of_bits) { Bit_flags* pBit_flags; if(number_of_bits > 0) // The given number is positive { pBit_flags = (Bit_flags*)malloc(sizeof(Bit_flags)); if(pBit_flags != NULL) { pBit_flags->capacity = sizeof(int); pBit_flags->size = number_of_bits; pBit_flags->bit = (int*)malloc(sizeof(int)); if(pBit_flags->bit != NULL) { *pBit_flags->bit = 0; } else { printf("Could not set memory for bit value.\n"); pBit_flags = NULL; } } printf("Bit flags object memory print created!\n\n"); } else // Given number was 0 or negative { printf("Number of bits cannot be negative.\n"); pBit_flags = NULL; } return pBit_flags; } Status bit_flags_set_flag(BIT_FLAGS hBit_flags, int flag_position) { Status stat; int bit_to_set = flag_position; int* temp; Bit_flags* phBit_flags =…def main(): x = 1 y = 2 swap(x, y) print(x, y) def swap(s1, s2): temp = s1 s1 = s2 s2= temp main() Modify the code so that it actually swaps the values of x and y, without using the temp variable in the swap function.
- i=0; While(i<=14) {cout<A program of 33 bytes is loaded into memory. The Data Segment is shown below: .DATA X DB 3Ah, 12, 10101101b S DB 5 DUP(3Bh) Y DW 33ABh What is the offset address of Y? 0000 0009 0008 0007Q1: Correct the following code, then list the functions of this code. const int Sensorl = A1 // analog pin const int Batt = A0; // analog pin const byte interruptpin = 2; void setup() { Serial.begin(6900): pinMode(interruptPin, INPUT); } void loop) { attachInterrupt(2,tilt sensor.RISING): } void send() { int valuel = analogRead(Sensol): float millivolts = (valuel / 1024.0) * 5000; celsius = millivolts / 10; Serial.printin(celseus); delay(1000); int valuel = analogRead(Batt) float Battery = (value2 / 1024.0) * 500; Battery-Battery/1000; Serial.printin(Battery); delay(1000); detachinterrupt(0); }Menus The local diner offers a meal combination consisting of an appetizer, a soup, a main course, and a dessert. There are four appetizers, five soups, three main courses, and four desserts. Your diet restricts you to choosing between a dessert and an appetizer. (You cannot have both.) Given this restriction, how many three-course meals are possible? A computer byte consists of eight bits, each bit being either a 0 or a 1. Assume that characters are represented using a code that uses a byte for each character. Some written languages, such as Chinese and Japanese, use tens of thousands of different characters. If a language uses roughly 97,000 characters, a computer code for this language would have to use how many bytes per character?What is the signature of a pointer that can only point to a fixed memory location?In execution of the following code with the following bytes contents: START: CLC MOV CX, 0002 MOV SI, 0300 MOV DI, 0302 LOOP: MOV AL, (DI) ADC (SI), AL INC SI INC DI DEC CX JNZ LOOP HLT (0300H) = 1AH, (0301H) = 2BH, (0302H) = 3CH, (0303H) = 4DH. %3D %3D %3D The result will be:SEE MORE QUESTIONS