Move one cell left: (0, 0, 0, L, 1) (0, 1, 1, L, 1) Add 1 (1, 0, 1, L, 2) Move left (1, 1, 0, L, 1) Carry (1, A, 1, S, halt) Done Find left end of the string (2, 0, 0, L, 2) (2, 1, 1, L, 2) (2, A, A, R, halt) Done In the following, fill out the blanks in the following sum computation process for the given natural number 54 (= 1101102). For each step, put the instruction to be used for that step in the blank on the left side, and fill out the blank(s) in the I/O tape on the right side. (1 point each blank) 10 A110110 A (instruction for this step) (instruction for this step) State=0 10 A110110 A State = 10 A110100A (instruction for this step) State= 10 A110000A (instruction for this step) State (instruction for this step) 10 A111000A State = From this point on, every digit read by the TM will be kept the same until the left end of the string is reached.
Move one cell left: (0, 0, 0, L, 1) (0, 1, 1, L, 1) Add 1 (1, 0, 1, L, 2) Move left (1, 1, 0, L, 1) Carry (1, A, 1, S, halt) Done Find left end of the string (2, 0, 0, L, 2) (2, 1, 1, L, 2) (2, A, A, R, halt) Done In the following, fill out the blanks in the following sum computation process for the given natural number 54 (= 1101102). For each step, put the instruction to be used for that step in the blank on the left side, and fill out the blank(s) in the I/O tape on the right side. (1 point each blank) 10 A110110 A (instruction for this step) (instruction for this step) State=0 10 A110110 A State = 10 A110100A (instruction for this step) State= 10 A110000A (instruction for this step) State (instruction for this step) 10 A111000A State = From this point on, every digit read by the TM will be kept the same until the left end of the string is reached.
Database System Concepts
7th Edition
ISBN:9780078022159
Author:Abraham Silberschatz Professor, Henry F. Korth, S. Sudarshan
Publisher:Abraham Silberschatz Professor, Henry F. Korth, S. Sudarshan
Chapter1: Introduction
Section: Chapter Questions
Problem 1PE
Related questions
Question
The following is the instruction set of a Turing machine (TM) that computes
the sum of 2 and a given natural number represented as a binary string. The
read/write head of the TM starts at the right end of the given natural number
and halts at the left end of the output string. The start state of the TM is 0.
(fill in the blanks as needed, write on the screenshot if possible)
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