mm diameter and a drive pulley of 200 mm diameter, whose centres are 1000 mm apart. The driving pulley is turned by a motor running at 600 rpm. The driven pulley exerts a torque of 40 Nm on a machine. Calculate the maximum power which can be transmitted through the belt drive if the coefficient of friction is 0.3, and the maximum allowable tension in the

mm diameter and a drive pulley of 200 mm diameter, whose centres are 1000 mm apart. The driving pulley is turned by a motor running at 600 rpm. The driven pulley exerts a torque of 40 Nm on a machine. Calculate the maximum power which can be transmitted through the belt drive if the coefficient of friction is 0.3, and the maximum allowable tension in the

International Edition---engineering Mechanics: Statics, 4th Edition

4th Edition

ISBN:9781305501607

Author:Andrew Pytel And Jaan Kiusalaas

Publisher:Andrew Pytel And Jaan Kiusalaas

Chapter7: Dry Friction

Section: Chapter Questions

Problem 7.57P: The square-threaded screw with a pitch of 10 mm and a mean radius of 18 mm drives a gear that has a...

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Solve Sample Problem 7.16 if the contact pressure under the polisher varies parabolically from p0 at r=0 to zero at r=R; that is, p=p0(1r2/R2).
Power is transmitted between two shafts by a V-belt whose mass is 0.9 kg/m length. The maximum permissible tension in the belt is limited to 2.2 kN. The angle of lap is 170° and the groove angle 45°. If the coefficient of friction between the belt and pulleys is 0.17, find : 1. velocity of the belt for maximum power; and 2. power transmitted at this velocity. Note: Sketch the belt drive system for both parts and label the given data on it.
A multiple V-belt drive is required to transmit 4 kW. The smaller pulley of the system is150 mm diameter, rotates at 200 rev/min, and has an angle of lap angle of 135°. Thegrove angle is 40° and the coefficient of friction between the belt and the pulleys is 0·3.If the maximum tension in any one belt is limited to 800 N, calculate:(a) The number of belts required. (b) The minimum tension in any one belt. (c) The required pre-tensioning of the belt. The centre-to-centre distance between the pulleys is 2 m.(d) Determine to the nearest mm, the required size for the larger pulley.(e) Find the approximate length of the belt
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An elevator type lift is being designed to raise a load up to 5,000pounds between floors. Two square-thread lead screws, 1.5 inches in (major) diameter, are used for this application. Determine the torque required to raise this lift if the moving part of the elevator weighs 800 pounds and the coefficient of friction is assumed to be 0.15. For the elevator described, find the efficiency and power required if each lead screw is driven at 175 rpm. Verify if this is self locking.
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In an engine governor of the Porter type, the upper and lower arms are 200 mm and 250 mm respectively and pivoted on the axis of rotation. The mass of the central load is 15 kg, the mass of each ball is 2 kg and friction of the sleeve together with the resistance of the operating gear is equal to a load of 24 N at the sleeve. If the limiting inclinations of the upper arms to the vertical are 30° and 40°, find, taking friction into account, range of speed of the governor.
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The tension in a pulley belt is 300 N when stationary. The smaller pulley has a diameter of 300 mm and a speed of 1420 rev/min. The coefficient of friction between the belt and the pulley is 0·4 and the angle of lap is 160°. (a) Calculate the tension in each side of the belt at operating speed. (b) Determine the power transmitted when the belt is on the point of slipping. If the pulley system uses a flat belt of CSA 500 mm² and density 1300 kg/m3, determine: (c) The power transmitted, when the mass of the belt is taken into consideration.