Match the transfer function with correct Bode amplitude plots.✓G(s):5s+7G(s)=s+5G(s):s+ 10SSG(s) =s+ 10A.B.D.slope 20 dB/dec=slope = -20 dB/dec=slope 20 dB/dec=slope -20 dB/dec

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Answered: Match the transfer function with…

Elements Of Electromagnetics

7th Edition

ISBN:9780190698614

Author:Sadiku, Matthew N. O.

Publisher:Sadiku, Matthew N. O.

ChapterMA: Math Assessment

Section: Chapter Questions

Problem 1.1MA

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Match the transfer function with correct Bode amplitude plots. G(s) = s+ 10 s(+100) s+ 100 G(s) = s(s+10) S G(s)= (s+10) (s+100) (+10) G(s) = (+100) s(+100) G(s) = (+10) (+10)(+100) G(s) = S A. -20 dB/dec 20 dB/dec B. D. 20 dB/dec -20 dB/dec 20 dB/dec -40 dB/dec -20 dB/dec 20 dB/dec 40 dB/dec E. 20 dB/dec -20 dB/dec 20 dB/dec 20 dB/dec -20 dB/dec
5 Problem Match the following two frequency response diagrams: -0 0.4 |G(i w)| 0.2 10 |G(i w)| 5 Response A 2 3 4 5 6 7 8 Frequency, (rad/s) Response B 5 6 7 8 Frequency, w(rad/s) 1 2 3 4 6 6 10 10 10 to two of the following ODES 1. +x+100x = u(t) 5. +100x = u(t) 9. +100x = u(t) 3. x+x+5x= u(t) 4. x+x+x= u(t) 2. x+x+25x = u(t) : 6. x + 25xu(t) 10. +25x = u(t) 7. x+5x= u(t) 8. u(t) 11. +5x= u(t) = 12. xu(t)
Graph/Plot the output step response from t=0 to t=10 with a 0.1-second interval.
Match the transfer function with correct Bode amplitude plots. G(s)= S s²+7s+10 S G(s) = s² + 10s+ 100 s+1 G(s) = s²+10x+100 S+ 10 G(s) = G(s) = s²+s+10 s+ 10 s²+101s+ 100 A. 20 dB/dec -20 dB/dec B. -20 dB/dec -20 dB/dec C. 20 dB/dec 20 dB/dec E. 20 dB/dec -20 dB/dec -40 dB/dec -20 dB/dec
H-W Find Time response for 2S+3 Yes)= s° (s+3)
Match the transfer function with correct Bode phase plots. G(s) = 5 $+7 G(s)=s+5 G(s) = s+10 S S G(s) = S+ 10 QUESTION 10 90 deg 00 0 deg -90 deg 180 deg B. D 90 deg @ 0 deg -90 deg 180 deg 90 deg @ 0 deg -90 deg 180 deg 90 deg @ 0 deg -90 deg 180 deg
Match the transfer function with correct Bode phase plots. s+10 G(s)=(s+100) s+ 100 G(s)= s(s+10) G(s) = (s+10) (s+100) s(s+10) G(s) = (s+100) s(s+100) G(s)= (s+10) G(s) = (+10) (+500) S A. 180 deg- 90 deg 0 deg 90 deg 180 deg- 90 deg 00 00 0 deg C. 90 deg+ 90 deg+ 0 deg -90 deg D. 180 deg F. 90 deg 0 deg 90 deg -180 deg 90 deg 0 deg 90 deg -180 deg 90 deg 0 deg -90dex+ -180 deg 00
1) Consider the baseband pulse x(1) = n(2) = 11 a) Derive the complex ambiguity function for x(t) and compare your result with the one obtained in class. b) Use MATLAB to compute the complex ambiguity function and compare it to part (a). c) Now, consider the pulse x(t) = sinc(Bt) i) Derive the complex ambiguity function for x(t) and compare to the ambiguity function of the rect pulse. Make your observations. ii) Plot the ambiguity function using the mesh function and using the contour function. iii) Use MATLAB to compute the complex ambiguity function and compare it to part (ii).
The Laplace transform of f t.cos 4t s2-16 f (s) = f(s) = (s2+16)2 (s2+16)2 Option 1 Option 2 s+4 f (s) s+1 f(s) : (s2-16)2 (s2+4)2 O Option 3
Design an analog Butterworth filter with the following properties. Find the transfer function Ap=2dB (Passband attenuation (rad/sec pass bondi frequency) (Wp 20 As 10 dB (Stop band attenuation rad/sec stop body frequency, (Ws) 30 Note: since wp and ws are analog frequencies (Unit rad/sec) you don't need to do a conversion If given in discrete time (Op and Os rad/sample) you would have to use the formula (W = 2/T tan (2))
Construct the Bode plots of the following transfer functions. Indicate Gain Margin and Phase Margin of the systems. a) b) 8 s(1.25s + 1)(s+2) 1.6 (s+0.4)(s+0.8) (s + 1)
10- The laplace transform of output variable to laplace transform of input variable is called as control system. Select one: True False

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Match the transfer function with correct Bode amplitude plots. ✓ G(s): 5 s+7 G(s)=s+5 G(s): s+ 10 S S G(s) = s+ 10 A. B. D. slope 20 dB/dec = slope = -20 dB/dec = slope 20 dB/dec = slope -20 dB/dec