#6 :) Trial #1Trial #21. Mass of the filter paper, g0.8330.62Mass of filter paper and precipitate, g453145642. Chemical equation:Al(NO3)3(aq)NaOH(aq)->3. N° moles AI(NO3)3(aq), mol4. N° moles NaOH(aq), mol5. Limiting reactant6. Reactant in excess

Since your question has multiple sub-parts, we will answer the first three sub-parts for you. If you…

Answered: Mass of the filter paper, g 0.833 0.862…

Mass of the filter paper, g 0.833 0.862 Mass of filter paper and precipitate, g 4.531 4564 Chemical equation: Al(NO3)3(aq) NaOH(aq)

Fundamentals Of Analytical Chemistry

9th Edition

ISBN:9781285640686

Author:Skoog

Publisher:Skoog

Chapter24: Introduction To Spectrochemical Methods

Section: Chapter Questions

Problem 24.18QAP

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Question

#6 :)

Trial #1
Trial #2
1. Mass of the filter paper, g
0.833
0.62
Mass of filter paper and precipitate, g
4531
4564
2. Chemical equation:
Al(NO3)3(aq)
NaOH(aq)
->
3. N° moles AI(NO3)3(aq), mol
4. N° moles NaOH(aq), mol
5. Limiting reactant
6. Reactant in excess

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