main() { int arr[] = {'A', 'B','C','D'}; int i; 6 7 8 9 for (i = 0; i <= 3; i++) 10 printf("\n%d", arr[i]); } } 11 12 13
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Study the block of codes below:
(see attached photo)
Which line of code will cause an error/problem when compiled/executed?
Step by step
Solved in 3 steps with 2 images
- in c language !! typedef struct {long restaurant_id;char restaurant_name[10];char description[120];double rate;char cuisine[30]; opening_year;long capacity;char city[30];char address[60];char owner[30];} RECORD_t, *RECORD; RECdelete (unsigned long restaurant_id, RECORD *restaurant_array, unsigned long *p_size){int rec;int index;// index <- find the index of the RECORD with given restaurant_id in restaurant_array ????? (I DIDNT)if (index is valid)rec=restaurant_array[index];elserec=NULL;return rec;}in c language !! typedef struct {long restaurant_id;char restaurant_name[10];char description[120];double rate;char cuisine[30]; opening_year;long capacity;char city[30];char address[60];char owner[30];} RECORD_t, *RECORD; RECORD delete (unsigned long restaurant_id, RECORD *restaurant_array, unsigned long *p_size){int rec;int index;// index <- find the index of the RECORD with given restaurant_id in restaurant_array ????? (I DIDNT)if (index is valid)rec=restaurant_array[index];elserec=NULL;return rec;}int sum = 0; for (int i 0; i < 5; i++){ sum += i; } cout << sum;
- int func(int a, int b) { return (aint* p: int a[3]{1, 2, 3}; p = a; What is the value of *(p+2)?double tab1[5] = {2,3,4,5,6}; double tab2[5] = {6,5,4,3,2}; for(int i = 0;i<5;i++) { tab1[i] = tab1[i]*tab2[i]; cout<<tab1[i]<<" "; } 12 15 16 15 16 15 15 16 15 12 12 15 16 15 12 12 15 12 15 12CFG: Example 1 • Draw the CFG for the following code: int f(int n){ } int m = n* n; if (n < 0) else return 0; return m;#include using namespace std; bool isPalindrome(int x) { int n=0,val; val = x; while(x > 0) { n = n * 10 + x % 10; x = x / 10; } } int main() { int n; cin >>n; if(isPalindrome(n)) { cout <#include using namespace std; int main() { int numbers[10]; int i; for (i=0;i>numbers[i]; int numbers2[10],j,k; for(i=0;ic) { max1=rep; c=top; } } cout<#include <stdio.h> struct dna { int number; char text; char stringvalue[30]; }; int main() { struct dna dnavalue[5]; int i; for(i=0; i<4; i++) { printf("Sample %d\n",i+1); printf("Enter Number:\n"); scanf("%d", &dnavalue[i].number); printf("Enter Text :\n"); scanf("%c",&dnavalue[i].text); printf("Enter String :\n"); scanf("%s",dnavalue[i].stringvalue); } printf("Sample DNA Number Text String\n"); for(i=0; i<4; i++) { printf("%d\t\t", i+1); printf("%d\t\t", dnavalue[i].number); printf("%c\t\t", dnavalue[i].text); printf("%s", dnavalue[i].stringvalue); printf("\n"); } return 0; } Write comments on every line of this program explaining what's happening brieflyMatch the C-function on the left to the Intel assemble function on the right. W: cmpl $4 movl %edi , %edi jmp .L4(,%rdi,8) %edi .L3: movl $17, %eax ret .15: movl $3, %eax int A ( int x , int y) { int a ; if ( x == 0 ) else i f ( x == 1 ) a = 3 ; else i f ( x == 2 ) a = 2 0 ; else i f ( x == 3 ) a = 2 ; else i f ( x == 4 ) a = 1 ; ret .L6: a = 17; movl $20, %eax ret .L7: movl $2, %eax ret else a = 0; .L8: return a ; movl $1, %eax .L2: ret . section .rodata . L4: .quad .L3 .quad .L5 .quad .L6 .quad .L7 .quad .L8 X: testl %edi, %edi je cmpl je cmpl je стр1 je cmpl .L16 $1, %edi .L17 $2, %edi .L18 $3, %edi int B (int x, int y) { int a; switch (x) { .L19 $4, %edi %al movzbl %al, %eax case 0: a = 17; break; sete break; case 1: a = 3; case 2: a = 20; break; case 3: a = 2; break; case 4: a = 1; a = 0; } return a; ret .L16: break; movl $17, %eax ret .L17: movl $3, %eax } ret .L18: movl $20, %eax ret .L19: movl ret $2, %eaxint main(){ long long int total; long long int init; scanf("%lld %lld", &total, &init); getchar(); long long int max = init; long long int min = init; int i; for (i = 0; i < total; i++) { char op1 = '0'; char op2 = '0'; long long int num1 = 0; long long int num2 = 0; scanf("%c %lld %c %lld", &op1, &num1, &op2, &num2); getchar(); long long int maxr = max; long long int minr = min; if (op1 == '+') { long long int sum = max + num1; maxr = sum; minr = sum; long long int res = min + num1; if (res > maxr) { max = res; } if (res < minr) { minr = res; } } else { long long int sum = max * num1; maxr = sum; minr = sum; long long int res = min * num1;…SEE MORE QUESTIONS