m1= 2kg V1=10 m/s (east) m2=10kg V2=20 m/s (30 south of west) The collision is completely inelastic. A. Find the x-velocity after the collision ( V'x). B. Find the y-velocity after the collision ( V'y).
m1= 2kg V1=10 m/s (east)
m2=10kg V2=20 m/s (30 south of west)
The collision is completely inelastic.
A. Find the x-velocity after the collision ( V'x).
B. Find the y-velocity after the collision ( V'y).
C. Represent the final velocity vector ( V') graphically
D. Find the magnitude |V'|
E. Find the direction.
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Given quantities:
m1 = 2 kg , V1 = 10 m/s ( east )
m2 = 10 kg , V2 = 20 m/s ( 30 degree south of west )
It is known that in case of inelastic collision, the momentum of the system remains conserved and after collision, both the particles stick together.
First, write each velocities in component form as follows:
V1 = 10i
V2 = -20Cos(30)i - 20Sin(30)j = -17.32i - 10j
Now, calculate the initial momentum before collision as follows:
Pi = m1V1 + m2V2
= 210i + 10( -17.32i - 10j )
= - 153.2i - 100j
Similarly, the final momentum after collision will be :
Pf = ( m1 + m2 )V'
= 12V'
Now, as the total momentum remains conserved, this implies:
Pf = Pi
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