lues E. An alternating voltage is connected in series with a resistance R and an inductance L. If the potential drop across the resistance is 200 V and across the inductance is 150 V. then the applied voltage is (a) 350 V (b) 250 V (d) 300 V tago C (c) 500 V 300 5

University Physics Volume 2
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Chapter14: Inductance
Section: Chapter Questions
Problem 66P: The self-inductance and capacitance of an oscillating LC circuit are L = 20 mH and C = 1.0 F ,...
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he
IS
es
e
ht
es
d
Current, Voltage, RMS and Average Values
26. An alternating voltage is connected in series with a
resistance R and an inductance L. If the potential drop across
then the applied voltage is
the resistance is 200 V and across the inductance is 150 V.
(a) 350 V
(b) 250 V
(c) 500 V (d) 300 V
27. An alternating voltage E = 200√2 sin (100t) is connected to
a 1 μF capacitor through an AC ammeter. The reading of the
ammeter shall be
(a) 10 mA
(c) 40 mA
28. In the circuit shown, the AC source has voltage
V = 20 cos (@t) volt with @= 2000 rad/s the amplitude of the
current will be nearest to
5 mH, 40
voor
(a) 0
Current
(a) 2 A
(b) 3.3 A
(c) 2/√5A
(d) √5A
29. The rms voltage of the wave form shown is
Y
+10
0
(b) 20 mA
(d) 80 mA
-10
6Ω
50 μF
(b) 7 V
(a) 10 V
(c) 6.37 V
(d) None of these
30. The output sinusoidal current versus time curve of a rectifier
is shown in the figure. The average value of output current
in this case is
327
Time
AC civon
Transcribed Image Text:he IS es e ht es d Current, Voltage, RMS and Average Values 26. An alternating voltage is connected in series with a resistance R and an inductance L. If the potential drop across then the applied voltage is the resistance is 200 V and across the inductance is 150 V. (a) 350 V (b) 250 V (c) 500 V (d) 300 V 27. An alternating voltage E = 200√2 sin (100t) is connected to a 1 μF capacitor through an AC ammeter. The reading of the ammeter shall be (a) 10 mA (c) 40 mA 28. In the circuit shown, the AC source has voltage V = 20 cos (@t) volt with @= 2000 rad/s the amplitude of the current will be nearest to 5 mH, 40 voor (a) 0 Current (a) 2 A (b) 3.3 A (c) 2/√5A (d) √5A 29. The rms voltage of the wave form shown is Y +10 0 (b) 20 mA (d) 80 mA -10 6Ω 50 μF (b) 7 V (a) 10 V (c) 6.37 V (d) None of these 30. The output sinusoidal current versus time curve of a rectifier is shown in the figure. The average value of output current in this case is 327 Time AC civon
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