Location A is 2.00 m to the right of a point charge q. Location B lies on the same line and is 3.60 m to the right of the charge. Thepotential difference VB - VA = 41.0 V. What is the magnitude and sign of the charge?I9IKBIAB

Answered: Location A is 2.00 m to the right of a…

College Physics

1st Edition

ISBN:9781938168000

Author:Paul Peter Urone, Roger Hinrichs

Publisher:Paul Peter Urone, Roger Hinrichs

Chapter19: Electric Potential And Electric Field

Section: Chapter Questions

Problem 34PE: (a) What is the potential between two points situated 10 cm and 20 cm from a 3.0 C point charge? (b)...

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Location A is 2.00 m to the right of a point charge q. Location B lies on the same line and is 3.60 m to the right of the charge. The
potential difference VB - VA = 41.0 V. What is the magnitude and sign of the charge?
I
9
I
K
B
I
A
B

Expert Solution

Step 1

The work done amount required to relocate an unit charge in an electric field of a charge from one point to another is termed as the potential difference.

Here in this case the given potential difference is

$V_{B} - V_{A} = 41.0 V$ where $V_{A}$ is the potential of the position $A$ and $V_{B}$ is the potential at point $B$ .

Now, Distance of point $A$ is $r_{A} = 2.00 m$

Distance of point $B$ is $r_{B} = 3.60 m$

Now the formula to calculate the potential at point $A$ is given by

$V_{A} = \frac{K q}{r_{A}}$ where $K$ is the Coulomb Constant and $q$ is the concerned charge.

Now the formula to calculate the potential at point $B$ is given by

$V_{B} = \frac{K q}{r_{B}}$

Note: $K = 8.99 \times 10^{9} N . m^{2} . C^{- 2}$

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