given answer with explanation in TYPED form Page 1:2:E1) ListenThe data in the table below were obtained for the reaction:H2 (g) + 12 (g) → 2 HI(g)ExperimentNumber [H₂] (M)1230.1000.1000.3000.29 M/s0.031 M/s0.291 M/sO.0291 M/s0.029 M/s[12₂] (M)0.100.400.10Initial Rate(M/s)0.00500.0800.045188ATUsing the Rate law determined from this data. What is the rate if [H₂] = 0.25[12] = 0.305M

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Listen The data in the table below were obtained for the reaction: H2 (g) + 12 (g) Experiment Number 1 2 3 - 2 HI(g) [H₂] (M) [12] (M) 0.10 0.40 0.10 0.100 0.100 0.300 Initial Rate (M/s) 0.0050 0.080 0.045 Using the Rate law determined from this data. What is the rate if [H₂] = 0.25 [12] = 0.305M

Listen The data in the table below were obtained for the reaction: H2 (g) + 12 (g) Experiment Number 1 2 3 - 2 HI(g) [H₂] (M) [12] (M) 0.10 0.40 0.10 0.100 0.100 0.300 Initial Rate (M/s) 0.0050 0.080 0.045 Using the Rate law determined from this data. What is the rate if [H₂] = 0.25 [12] = 0.305M

Chemistry: An Atoms First Approach

2nd Edition

ISBN:9781305079243

Author:Steven S. Zumdahl, Susan A. Zumdahl

Publisher:Steven S. Zumdahl, Susan A. Zumdahl

Chapter11: Chemical Kinetics

Section: Chapter Questions

Problem 97CWP: A reaction of the form aAProducts gives a plot of ln[A] versus time (in seconds), which is a...

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