Let s(t) - 8t³ – 24t? – 192t be the equation of motion for a particle. Find a function for the velocity. v(t) Where does the velocity equal zero? [Hint: factor out the GCF.] t and t Find a function for the acceleration of the particle. a(t) =
Let s(t) - 8t³ – 24t? – 192t be the equation of motion for a particle. Find a function for the velocity. v(t) Where does the velocity equal zero? [Hint: factor out the GCF.] t and t Find a function for the acceleration of the particle. a(t) =
Calculus For The Life Sciences
2nd Edition
ISBN:9780321964038
Author:GREENWELL, Raymond N., RITCHEY, Nathan P., Lial, Margaret L.
Publisher:GREENWELL, Raymond N., RITCHEY, Nathan P., Lial, Margaret L.
Chapter4: Calculating The Derivative
Section4.2: Derivatives Of Products And Quotients
Problem 4E
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Let s(t)= 8t^3−24t^2−192t be the equation of motion for a particle. Find a function for the velocity.
v(t)= (ans)
Where does the velocity equal zero? [Hint: factor out the GCF.]
t= (ans) and t= (ans)
Find a function for the acceleration of the particle.
a(t)= (ans)
![Let s(t)
- 8t³ – 24t? – 192t be the equation of motion for a particle. Find a function for the velocity.
v(t)
Where does the velocity equal zero? [Hint: factor out the GCF.]
t
and t
Find a function for the acceleration of the particle.
a(t) =](/v2/_next/image?url=https%3A%2F%2Fcontent.bartleby.com%2Fqna-images%2Fquestion%2F44c3b237-e4ca-4e38-a278-251c2495f1b6%2Fa82d5bb2-fe05-47df-b263-7b27eb7519b6%2F6w85yc_processed.png&w=3840&q=75)
Transcribed Image Text:Let s(t)
- 8t³ – 24t? – 192t be the equation of motion for a particle. Find a function for the velocity.
v(t)
Where does the velocity equal zero? [Hint: factor out the GCF.]
t
and t
Find a function for the acceleration of the particle.
a(t) =
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