Let n be an integer, use the definition of even to prove that 18n + 2 is even. 18n+2= Since X is an integer, is also an integer. Since 18n + 2 equals 2 times an integer, 18n + 2 is even.

Operations Research : Applications and Algorithms
4th Edition
ISBN:9780534380588
Author:Wayne L. Winston
Publisher:Wayne L. Winston
Chapter2: Basic Linear Algebra
Section: Chapter Questions
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Let n be an integer, use the definition of even to prove that 18n + 2 is even.
18n + 2 =
Since
X
is an integer,
is also an integer.
Since 18n +2 equals 2 times an integer, 18n + 2 is even.
Transcribed Image Text:Let n be an integer, use the definition of even to prove that 18n + 2 is even. 18n + 2 = Since X is an integer, is also an integer. Since 18n +2 equals 2 times an integer, 18n + 2 is even.
Let n be an integer, use the definition of odd to prove that 18n + 7 is odd.
18n+7= 18
Since
X 7
is an integer,
+1.
is also an integer.
Since 18n +7 equals 2 times an integer plus one, 18n + 7 is odd.
Transcribed Image Text:Let n be an integer, use the definition of odd to prove that 18n + 7 is odd. 18n+7= 18 Since X 7 is an integer, +1. is also an integer. Since 18n +7 equals 2 times an integer plus one, 18n + 7 is odd.
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