Let f(x)=x² -3x+5. Show that the average rate of change of f (with respect to x) on an arbitrary interval [a , b] is equal to the instantaneous rate of change of f at the midpoint of that interval. Show and explain your work. (Note: This will be true for any quadratic function, and not just for the given one.)

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Q: use the second derivative test to find the local exterma of the function f(x) =x3 -9x2-48x+72 on R

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A: topic - average rate of change of function over interval

Q: Find the average rate of change of the function f(x) = x² -3x + 5 between x = 0 and x = 2.

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Q: 1. What is the average rate of change of the function f(x) = x² - 4x + 7 on the interval 1 ≤ x ≤ 3?

A: average rate fo change in an interval (a,b) =f(b)-f(a)b-a