Let Find с S = 2=-t P(2) q(z) be the 2²-1 Sinz poles inside the circle By residue theorem 250i/Res 22-1 Sinz = dz __2²_1 circle Sinz + Res 2²-1 Z=0 Sinz |z 2Ji = 2,5 i (1- JT ³² -1 + 1 - JT ²) - (2 ST - 4st ³) (₂ 3 Анд ore + residue → _p(2) 9'(2) at z =- J, 0, JT Res 2=J ((-³) -1 + = +*+ ² =1) Z²-1 Sinz cosz

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