Let A(t) = [3 sin(t) 3 sin(t) -5 cos(t)] 5 cos(t)] a. Find the values of t such that A(t) is not invertible. You may use k to denote any possible integer in your answer (e.g., if the answer is all integer multiples of 5, you would enter 5k, where k is any integer). A(t) is not invertible when t = where k is any integer. b. Find a formula for A-¹(t) for the values of t for which A(t) is invertible. A-¹ (t) =
Let A(t) = [3 sin(t) 3 sin(t) -5 cos(t)] 5 cos(t)] a. Find the values of t such that A(t) is not invertible. You may use k to denote any possible integer in your answer (e.g., if the answer is all integer multiples of 5, you would enter 5k, where k is any integer). A(t) is not invertible when t = where k is any integer. b. Find a formula for A-¹(t) for the values of t for which A(t) is invertible. A-¹ (t) =
Algebra & Trigonometry with Analytic Geometry
13th Edition
ISBN:9781133382119
Author:Swokowski
Publisher:Swokowski
Chapter7: Analytic Trigonometry
Section7.3: The Addition And Subtraction Formulas
Problem 80E
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