Jump to level 1Compute: z = √xEx: If the input is 4.0 2.0, then the output is:4.01 #include 2 #include <3 #include 4 using namespace std;56 int main() {7double x;8 double y;9 double z;1011 cin >> X;cin >> y;121300 ChSEEEEEEEE1415V* Your code goes here */16 cout << fixed <<<

Include the necessary libraries for input/output, mathematical functions, and output…

Jump to level 1 Compute: z = √x Ex: If the input is 4.0 2.0, then the output is: 4.0 1 #include 2 #include 3 #include 4 using namespace std; 5678SOH 6 int main() { double x; double y; double z; 9 10 11 संलललललल cin >>> X; 12 cin >> y; 13 14 15 345678 16 17 18 19 20 } V* Your code goes here */ cout << fixed <<

Jump to level 1 Compute: z = √x Ex: If the input is 4.0 2.0, then the output is: 4.0 1 #include 2 #include 3 #include 4 using namespace std; 5678SOH 6 int main() { double x; double y; double z; 9 10 11 संलललललल cin >>> X; 12 cin >> y; 13 14 15 345678 16 17 18 19 20 } V* Your code goes here */ cout << fixed <<

EBK JAVA PROGRAMMING

9th Edition

ISBN:9781337671385

Author:FARRELL

Publisher:FARRELL

Chapter8: Arrays

Section: Chapter Questions

Problem 18RQ

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1 @include 2 using namespace std3; 3 int maxResult() 4-( int maxVal 7. for (int i = 0; i < n; i + a) { for (int j { float z = 8- 9. 0; j <= n i; j += b) %31 10 (float) (n (i + j)) / (float)(c); 11 12 if (floor(z) { int x = i / a; int y = 13 ceil(z)) ニニ 14 15 16 =j/ b; maxVal = max(maxVal, x + y + (int)z); 17 18 19 20 21 22 return maxVal; 23 } 24 25 int main() 26 - { 27 28 cout << maxResult( ); 29 30 return 0; 31 } Input ompilation failed due to following enor main.cpp:7:23: error: 'n' was not declared in this scope 7 for (int i 0; i <= n; i t a) nain.cpp:7:31: error: 'a' was not declared in this scope 7| for (int i - 0; i <= n; i + a) main.cpp:9:36: error: b' was not declared in this scope 1 6 for (int j = 0; j <= n i; j b) ain.cpp:11:45: error: 'c' was not declared in this scope
12.14 Zylab 3 - Single Procedure Call Given an array of at least one integer, write a program to create a new array with elements equal to the power of each element in the original array raised to the index, i.e., P[i] = A[i]^i. For this, write two functions that will be called in main function independently. ● power inputs: element (A[i]) and index (1) • task: returns the value of element raised to index (A[i]^i). } O • newElement inputs: base address of new array P (*P), current size of P (variable k) and the new element (A[i]^i) o task: add the new element at the end. o This function does not return any value (void). O Following is a sample C code to perform the required task. You may modify the code for the functions, but the task performed should not be changed. int main() { // Variable Declaration int *A, *P; int n, k; int pow; // Task of main function P[0] 1; for (int j = k = j; pow // Base addresses of A and P // Lengths of arrays A and B // Return value from power function }…
main.cpp:4:17: error: 'string' has not been declared 4 | void KMPSearch(string pat, string txt) main.cpp:4:29: error: string' has not been declared 4 | void KMPSearch(string pat, string txt) Aununun main.cpp:31:25: error: string' has not been declared 31 | void computelPSArray(string pat, int M, int[] lps) main.cpp:31:50: error: expected or . before lps' 31 | void computeLlPSArray(string pat, int M, int[] lps) main.cpp:55:8: error: expected :' before 'static' 55 | public static void Main() main.cpp:61:2: error: expected ;' after class definition 61 | } | main.cpp: In member function 'void GFG::KMPSearch(int, int)': main.cpp:6:15: error: request for member Length' in 'pat', which is of non-class type 'int' 6 | int M = pat.Length; main.cpp:7:15: error: request for member Length' in txt’, which is of non-class type 'int' int N = txt.Length; main.cpp:8:6: warning: structured bindings only available with -std3c++17' or (-std=gnu++17' 8 | int[] lps new int[M];
Load the picture named fname into memory and print its width, height, and bytes-per-pixel. graphics.cpp 1 #define ... 2 #define 3 #include 4 #include 5 #include 6 #include 7 using namespace std; 8 9 int main() 10 { 11 12 string fname = "pete.png"; int width, height, bpp, channels = 4; unsigned char * const if (...) 13 14 15 16 17 18 cout « "Cannot load " <« fname <« endl; else { cout « fname <« " was loaded in memory" <« endl; cout « "width: " « endl; cout « "height: cout « "byte-per-pixel: } 19 20 21 « endl; " « endl; 22 23 }
Outputs of the following: void main () { int M[3]; int *ptr; ptr=M; *ptr=D100; ptr++; *ptr=200; ptr=&M[2]; *ptr=300; for (int n=O; n<3; n++) cout <
The code box below defines a variable route as a list of directions to navigate a maze. Each instruction is one of the following four basic commands: higher move one step in the positive y direction • lower. move one step in the negative y direction • left: move one step in the negative x direction • right: move one step in the positive x direction Define a function step that takes two arguments, a location (as a tuple of x and y coordinates) and an instruction (higher, lower, left, right) as a string. Given the provided location, it should return the new location (as a tuple of x and y coordinates) when following the specified instruction. If the instruction is invalid, the old location should be returned. Use the function step to determine the final position when starting from the point (0, -4) and following all instructions in the list route. Assign this final position to the variable final_point.
def accuracy(y, y_hat): # TODO 8.1 total_correct = # TODO 8.2 total_samples = print(f"Accuracy ratio: {total_correct}/{total_samples}") # TODO 8.3 return def TEST_accuracy(): dummy_y = np.ones([100, 1]) dummy_y_hat = np.ones([100, 1]) dummy_y_hat[90:] = -1 dummy_acc = accuracy(dummy_y_hat, dummy_y) print(f"Accuracy is: {dummy_acc}") todo_check([ (dummy_acc == .9,"Incorrect accuracy value") ]) TEST_accuracy() garbage_collect(['TEST_accuracy'])
Jump to level 1 Compute: z = √x-y Ex: If the input is 4.0 3.0, then the output is: 1.0 #include #include #include using namespace std; int main() { double x; double y; double z; :) } ctn >> X; cin >> y; /* Your code goes here */ cout << fixed <<
Case Diagram and UML Class Diagram for this java code : (Below the code give some constructive critiques about the UML class diagram)…. Thanks import java.util.*; public class BeverlyBreads{public static void main(String[] args){Scanner input = new Scanner(System.in); //Array for breads String[] breads = new String[5]; //Bread choices breads[0] = "White Bread"; breads[1] = "Wheat Bread"; breads[2] = "Rye Bread"; breads[3] = "Pumpernickel Bread"; breads[4] = "Baguette"; //Prices for the breads double[] prices = new double[5]; prices[0] = 2.99; prices[1] = 3.49; prices[2] = 3.99; prices[3] = 4.49; prices[4] = 4.99; //Customer's Name System.out.println("Enter customer's name: "); String name = input.nextLine(); //Customer's Phone Number System.out.println("Enter customer's phone number: "); String phoneNumber = input.nextLine(); //Bread Selection System.out.println("Which bread would you like to order?"); for(int i = 0; i < breads.length; i++) { System.out.println(breads[i] + "…
#include int main() { int a[5]; for (int i = = a[i] 1; for (int j = 0; j = a) { } = int n *pa; while (n >= 1) { n = n / 2; printf("%d *pa); pa-- ; 2 1; } Q. What is the output?
please help me with the following 1) make a sierpenski triangle using java and recursion. Make it similar to the code below. And please comment the code 2) Please make the follow code out put on the console. It a t square fractal import java.awt.image.*;import java.awt.Color;import java.io.*;import javax.imageio.*; public class Main{ static final int DIMENSION = 1000; static BufferedImage image = new BufferedImage(DIMENSION, DIMENSION, BufferedImage.TYPE_INT_RGB); static final int WHITE = Color.WHITE.getRGB(); static final int BLACK = Color.BLACK.getRGB(); private static void drawSquare(int x, int y, int side) { if (side <= 0) return; else { int left = x - side/2; int top = y - side/2; int right = x + side/2; int bottom = y + side/2; for (int i = left; i < right; i++) for (int j = top; j < bottom; j++) { image.setRGB(i, j, BLACK); }…
change to ada language import java.util.scanner; public class problem41 { public static void main(string[] args) { scanner input = new scanner(system.in); int positives = 0; // count the number of positive numbers int negatives = 0; // count the number of negative numbers int count = 0; // count all numbers double total = 0; // accumulate a totol // promopt the user to enter an integer or 0 to exit system.out.print("enter an integer, the input ends if it is 0: "); int number = input.nextint(); if (number == 0) { // test for sentinel value system.out.println("no numbers are entered except 0"); system.exit(1); } while (number != 0) {// test for sentinel value if (number > 0) { positives++; // increase positives } else { negatives++; // increase negatives } total += number; // accumulate total count++; // increase the count number = input.nextint();//read the next number } // calculate the average double average = total / count; // display results system.out.println( "the number of…