Jointly Gaussian random variables play an important role in probability theory, due partly to the fact that linear combinations of Gaussians are themselves Gaussian. This allows us to answer complex questions by only calculating means and variances. Here, we will explore an application of this phenomenon to the expected value. Let X₁,..., ✗n be independent Gaussian random variables, with expected values E[X¿] = μ and variances Var[X¿] σ² for i = 1,...,n and let 1 n = Y = Σ X; be their average. Intuitively, the random variable Y should get “closer" to μ as n i=1 the number of samples n increases. Below, we will try to make this intuition precise. 1 X1 (a) Define X = Determine its mean vector E[✗] and covariance matrix Σx. Xn (b) Express Y = AX for some matrix A. (Note that row vectors and column vectors are special cases of matrices.) (c) Determine E[Y]. (d) Determine Var[Y]. (e) Calculate the probability that Y is more than 8 > 0 away from its mean, P[|Y − E[Y]| > 6]. Express your answer in terms of the standard normal complementary CDF Q(z) = 1- Þ(z) or the standard normal. (f) Using the fact that Q(3.29) = 2000, calculate how many samples n are needed, as a function of the variance o² to guarantee that P[|Y - E[Y]| > 10] is 1000 or smaller.
Jointly Gaussian random variables play an important role in probability theory, due partly to the fact that linear combinations of Gaussians are themselves Gaussian. This allows us to answer complex questions by only calculating means and variances. Here, we will explore an application of this phenomenon to the expected value. Let X₁,..., ✗n be independent Gaussian random variables, with expected values E[X¿] = μ and variances Var[X¿] σ² for i = 1,...,n and let 1 n = Y = Σ X; be their average. Intuitively, the random variable Y should get “closer" to μ as n i=1 the number of samples n increases. Below, we will try to make this intuition precise. 1 X1 (a) Define X = Determine its mean vector E[✗] and covariance matrix Σx. Xn (b) Express Y = AX for some matrix A. (Note that row vectors and column vectors are special cases of matrices.) (c) Determine E[Y]. (d) Determine Var[Y]. (e) Calculate the probability that Y is more than 8 > 0 away from its mean, P[|Y − E[Y]| > 6]. Express your answer in terms of the standard normal complementary CDF Q(z) = 1- Þ(z) or the standard normal. (f) Using the fact that Q(3.29) = 2000, calculate how many samples n are needed, as a function of the variance o² to guarantee that P[|Y - E[Y]| > 10] is 1000 or smaller.
Calculus For The Life Sciences
2nd Edition
ISBN:9780321964038
Author:GREENWELL, Raymond N., RITCHEY, Nathan P., Lial, Margaret L.
Publisher:GREENWELL, Raymond N., RITCHEY, Nathan P., Lial, Margaret L.
Chapter13: Probability And Calculus
Section13.CR: Chapter 13 Review
Problem 8CR
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Only c, d, e, f please. Thanks!
![Jointly Gaussian random variables play an important role in probability theory, due partly to
the fact that linear combinations of Gaussians are themselves Gaussian. This allows us to answer
complex questions by only calculating means and variances. Here, we will explore an application
of this phenomenon to the expected value. Let X₁,..., ✗n be independent Gaussian random
variables, with expected values E[X¿] = μ and variances Var[X¿]
σ² for i = 1,...,n and let
1
n
=
Y = Σ X; be their average. Intuitively, the random variable Y should get “closer" to μ as
n
i=1
the number of samples n increases. Below, we will try to make this intuition precise.
1
X1
(a) Define X =
Determine its mean vector E[✗] and covariance matrix Σx.
Xn
(b) Express Y = AX for some matrix A. (Note that row vectors and column vectors are special
cases of matrices.)
(c) Determine E[Y].
(d) Determine Var[Y].
(e) Calculate the probability that Y is more than 8 > 0 away from its mean, P[|Y − E[Y]| > 6].
Express your answer in terms of the standard normal complementary CDF Q(z) = 1- Þ(z)
or the standard normal.
(f) Using the fact that Q(3.29) = 2000, calculate how many samples n are needed, as a function
of the variance o² to guarantee that P[|Y - E[Y]| > 10] is 1000 or smaller.](/v2/_next/image?url=https%3A%2F%2Fcontent.bartleby.com%2Fqna-images%2Fquestion%2F02681530-b6ca-4d72-bfd1-7260256101ab%2F70ba3dcc-ba29-4b15-9189-416ee2bc3b7b%2Fznsakh_processed.png&w=3840&q=75)
Transcribed Image Text:Jointly Gaussian random variables play an important role in probability theory, due partly to
the fact that linear combinations of Gaussians are themselves Gaussian. This allows us to answer
complex questions by only calculating means and variances. Here, we will explore an application
of this phenomenon to the expected value. Let X₁,..., ✗n be independent Gaussian random
variables, with expected values E[X¿] = μ and variances Var[X¿]
σ² for i = 1,...,n and let
1
n
=
Y = Σ X; be their average. Intuitively, the random variable Y should get “closer" to μ as
n
i=1
the number of samples n increases. Below, we will try to make this intuition precise.
1
X1
(a) Define X =
Determine its mean vector E[✗] and covariance matrix Σx.
Xn
(b) Express Y = AX for some matrix A. (Note that row vectors and column vectors are special
cases of matrices.)
(c) Determine E[Y].
(d) Determine Var[Y].
(e) Calculate the probability that Y is more than 8 > 0 away from its mean, P[|Y − E[Y]| > 6].
Express your answer in terms of the standard normal complementary CDF Q(z) = 1- Þ(z)
or the standard normal.
(f) Using the fact that Q(3.29) = 2000, calculate how many samples n are needed, as a function
of the variance o² to guarantee that P[|Y - E[Y]| > 10] is 1000 or smaller.
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