Jai + Ja₂ = I₁ + 1₂ + 13 Ja₂ = I₁ + 1₂ +13 - IG₁ Jaz = 139.96 20° +131.22 2-36.86 +98.982-45' - 150/-31-79* Jaz = 200 L-20144 A Armature current = 200 A Power factor = (os (20.44) 0.937 lagging Output =(√3 x 3300 x 200 x 0.937) KW Looo 1071 kw How did he get the value inside the circle? Can you explain step by step and clear line please?
Jai + Ja₂ = I₁ + 1₂ + 13 Ja₂ = I₁ + 1₂ +13 - IG₁ Jaz = 139.96 20° +131.22 2-36.86 +98.982-45' - 150/-31-79* Jaz = 200 L-20144 A Armature current = 200 A Power factor = (os (20.44) 0.937 lagging Output =(√3 x 3300 x 200 x 0.937) KW Looo 1071 kw How did he get the value inside the circle? Can you explain step by step and clear line please?
Power System Analysis and Design (MindTap Course List)
6th Edition
ISBN:9781305632134
Author:J. Duncan Glover, Thomas Overbye, Mulukutla S. Sarma
Publisher:J. Duncan Glover, Thomas Overbye, Mulukutla S. Sarma
Chapter2: Fundamentals
Section: Chapter Questions
Problem 2.2P: Convert the following instantaneous currents to phasors, using cos(t) as the reference. Give your...
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