J kg/hr of a mixture of benzene (B), Toluene (T) and Water (W) was fed to a distillation column as shown below. The mass flow rate of benzene in the top stream is 220 kg B/hr. The operation is at steady state. The mass flow rate of water at the bottom stream is 398.75 kg/hr. Calculate the unknown streams Y= 0.7 Xw= 0.45 Xg= 0.35 X= 0.20 Mw Ma - 0.19 MT O a. 687.5 kg/h O b. 1001.79 kg/h O c. 888.23 kg/hr O d. 1298.66 kg/h

J kg/hr of a mixture of benzene (B), Toluene (T) and Water (W) was fed to a distillation column as shown below. The mass flow rate of benzene in the top stream is 220 kg B/hr. The operation is at steady state. The mass flow rate of water at the bottom stream is 398.75 kg/hr. Calculate the unknown streams Y= 0.7 Xw= 0.45 Xg= 0.35 X= 0.20 Mw Ma - 0.19 MT O a. 687.5 kg/h O b. 1001.79 kg/h O c. 888.23 kg/hr O d. 1298.66 kg/h

Chemistry

10th Edition

ISBN:9781305957404

Author:Steven S. Zumdahl, Susan A. Zumdahl, Donald J. DeCoste

Publisher:Steven S. Zumdahl, Susan A. Zumdahl, Donald J. DeCoste

Chapter1: Chemical Foundations

Section: Chapter Questions

Problem 1RQ: Define and explain the differences between the following terms. a. law and theory b. theory and...

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J kg/hr of a mixture of benzene (B), Toluene (T) and Water (W) was fed to a distillation column as shown below. The mass flow rate of benzene in the top stream is 220 kg B/hr. The operation is at steady state. The mass flow rate of water at the bottom stream is 398.75 kg/hr. Calculate the unknown streams P Yw. YB- 0.7 YT Xw- 0.45 Xg= 0.35 Xr- 0.20 Mw MB = 0.19 MT a. 926.5 kg/h O b. 687.5 kg/h О с. 505 kg/h O d. 408.5 kg/h
A liquid mixture containing 40.0% benzene (B) and 60% toluene (T) by mass to the distillation column. The upper product stream contains 90 mol% B, and the lower product stream contains 6% of the benzene fed into the column (meaning that 94% of the benzene is left with the upper product). The volumetric flow rate of the feed is 2500 1/ hr and the specific gravity of .the feed mixture is 0.870 A- Rate of mass accumulation B- Component balance equation . The accumulation terms (d/ dt), can also be diminished to zero by assuming steady state
Q2: A stream of liquid water at a rate of N lit/s with a stream of methanol and ethanol mixture (contains 25 mol% methanol) are fed to continues evaporator. Another stream of methanol at a molar flow rate of G that of the alcohol mixture stream is fed to the same unit. If the liquids are evaporated totally and the produced vapor stream contains (0.1"G) mol% of water at a pressure of 28 psi and 220 F. calculate: 1- The flow rate and composition of all streams in a molar, mass, and volumetric basis 2- The average molecular mass of all streams The Specific gravity of methanol is 0.762 and that of ethanol is 0.789 while the density of vapors can be estimated as: p= p*Mw/RT where R-0.082 atm.m'/kmol.K.
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A mixture of ethanol (ethyl alcohol) and water contains 40.0% water by mass.(a) Assuming volume additivity of the components, estimate the specific gravity of themixture at 20°C. What volume (in liters) of this mixture is required to provide 150 mol ofethanol?(b) Repeat Part (a) with the additional information that the specific gravity of the mixture at20°C is 0.89045 (making it unnecessary to assume volume additivity). What percentage errorresults from the volume-additivity assumption?
In a process producing KNO3 salt, 1000 kg/h of a feed solution containing 10 wt% KNO3 is fed to an evaporator, which evaporates some water at 422 K to produce a 50 wt% KNO3 solution. This is then fed to a crystallizer at 311 K, where crystals containing 98 wt% KNO3 are removed. The saturated solution containing 37.5 wt% KNO3 is recycled to the evaporator. Calculate the amount of the recycle stream R in kg/h and the product stream of crystals P in kg/h.
1000 kg/hr of a mixture of benzene (B) and Toluene (T) containing 50% benzene by mass is separated by distillation into two fractions. The mass flow rate of benzene in the top stream is 450 kg B/hr and that of Toluene at the bottom is 475 kg T/h. the operation is at steady. What is the mass fraction of benzene at the bottom stream? О а. 0.015 O b. 0.095 О с. 0.23 O d. 0.132
A solution containing 100 lbm KNO 3/100 lbm H 2O at 80°C is fed to a cooling crystallizer operated at 25°C. Slurry from the crystallizer (KNO3 crystals suspended in saturated solution) is fed to a filter, where the crystals are separated from the solution. Use the solubility data in Figure 6.5-1 to determine the production rate of crystals (lbm/lbm feed) and the solid-to-liquid mass ratio (lbm crystals/lbm liquid) in the slurry leaving the crystallizer.
A mixture of methane and air is capable of being ignited only if the mole percent of methane is between 5% and 15%. A mixture containing 9.0 mole% methane in air flowing at a rate of 7:00 x 102 kg/h is to be diluted with pure air to reduce the methane concentration to the lower flammability limit. Calculate the required flow rate of air in mol/h and the percent by mass of oxygen in the product gas. (Note: Air may be taken to consist of 21 mole% O2 and 79% N2 and to have an average molecular weight of 29.0.)
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Q4/in a two stage process, acetic acid (A)is extracted from water (W) into hexanol (H) in a liquid-liquid extraction vessel and the extract is subsequently separated by distillation. Assume that water is completely insoluble in hexanol. A mixture of 18wt% acetic acid and the balance water is feed to liquid-liquid extraction vessel. Pure hexanol is feed to the column to extracted the acetic acid. The water-rich stream leaving the vessel is 99.5wt% water and the balance acetic acid. The hexanol-rich extract from the vessel is feed to a distillation column. The composition of the distillate is 96wt% acetic acid and the balance hexanol. The bottom stream contains 97.2wt% hexanol and recovers 95% of the hexanol feed to the liquid-liquid extraction vessel. Calculate the percentage of acetic acid in the process feed that is recovered in the distillate stream. Distillation Liq-liq Column Extraction