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- Which of the following molecules will NOT lead to a successful synthesis of a Grignard reagent upon reaction with magnesium? CI https://ibb.co/54Jw34p 2 Me. OMe https://ibb.co/6655LTH Br но https://ibb.co/2nfzPmX O Me `Br https://ibb.co/wo93ymS 2 Br MeO https://ibb.co/Hq2s6ck 2Predict the product(s) and provide the complete mechanism for each reaction below.- EtO₂C Show Transcribed Text Please draw the mechanism step by step LIAIH4, Et₂O puis H3O+ NaBH4, EtOH puis H3O+ MeMgBr (excès) puis H3O+ ? ? ?
- Draw the mechanism ffrom benzaldehyde to this using: i)NaBH4 ii)TsCl, py iii)NaCN iiii)H+, H2OWhich of the reagents listed below would efficiently accomplish the transformation of CH3CH₂CH=CHCH₂CH2CH2OH into CH3CH2CH=CHCH2CH2CHO? OKMnO4(aq, alkaline) O CrO3/H₂SO4 O PCC in CH₂Cl₂ O Br2 OTwo of these choices.Q4. Provide reagents for the following transformations OH ов ОН ОН
- Identify the suitable reagents for the given reaction and arrange them accordingly. 1 OH OEt 2 OEt OEt O 1) EtOH, H₂SO4; 2) EtOH, H₂SO4 O 1) EtONa followed by H₂O; 2) TsCl/py followed by EtONa O 1) EtONa followed by H₂O; 2) NaH followed by EtBr O 1) EtOH, H₂SO4; 2) NaH followed by EtBr O 1) EtOH, H₂SO4; 2) TsCy followed by EtONaMustard gas, Cl¬CH2CH2¬S¬CH2CH2¬Cl, was used as a poisonous chemical agentin World War I. Mustard gas is much more toxic than a typical primary alkyl chloride. Itstoxicity stems from its ability to alkylate amino groups on important metabolic enzymes,rendering the enzymes inactive.(a) Propose a mechanism to explain why mustard gas is an exceptionally potent alkylatingagentProvide a mechanism with products for the reaction above. CH3 2Na/Liq.NH₂