int x=20; int y=30; int z =y%2; z=0 Z=1 Z=15
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- Number of digits int main() {int c=0;int i=3856; int l=i; while(l>0) {l=l/10; c++; } printf("%d",c); return 0; } Summation of digits int main() {int sum=0; int i=384; int l=i; while(l>0) { sum+=l%10; l=l/10;} printf("%d",sum); return 0; }Example: Enter an integer = 75 Smallest divisor is = 3int x1 = 66; int y1 = 39; int d; _asm { } mov EAX, X1; mov EBX, y1; push EAX; push EBX; pop ECX mov d, ECX; What is d in decimal format?
- int sum = 0; for (int i 0; i < 5; i++){ sum += i; } cout << sum;int pertambahan(int pilihan, int now){ int result; result =pilihan + now; return result;} int perkalian(int pilihan, int now){ int result; result = pilihan*now; return result;} int main(){ int NoR,initial; int now; int temp1, temp2; scanf("%d %d", &NoR, &initial); getchar(); now=initial; for(int o=0;o<NoR;o++){ char a,b; int pilihan1,pilihan2; scanf("%c %d %c %d",&a, &pilihan1,&b, &pilihan2); getchar(); if(a=='+') { if(pilihan1>=-1000 && pilihan1<=1000) { temp1 = pertambahan(pilihan1,now); } else{ temp1=-10000; } } else if(a=='x') { if(pilihan1>=-2 && pilihan1<=2){ temp1 = perkalian(pilihan1,now); } else { temp1=-10000; } } if(b=='+') { if(pilihan2>=-1000 && pilihan2<=1000) { temp2 = pertambahan(pilihan2,now); } else {…Match the C-function on the left to the Intel assemble function on the right. W: cmpl $4 movl %edi , %edi jmp .L4(,%rdi,8) %edi .L3: movl $17, %eax ret .15: movl $3, %eax int A ( int x , int y) { int a ; if ( x == 0 ) else i f ( x == 1 ) a = 3 ; else i f ( x == 2 ) a = 2 0 ; else i f ( x == 3 ) a = 2 ; else i f ( x == 4 ) a = 1 ; ret .L6: a = 17; movl $20, %eax ret .L7: movl $2, %eax ret else a = 0; .L8: return a ; movl $1, %eax .L2: ret . section .rodata . L4: .quad .L3 .quad .L5 .quad .L6 .quad .L7 .quad .L8 X: testl %edi, %edi je cmpl je cmpl je стр1 je cmpl .L16 $1, %edi .L17 $2, %edi .L18 $3, %edi int B (int x, int y) { int a; switch (x) { .L19 $4, %edi %al movzbl %al, %eax case 0: a = 17; break; sete break; case 1: a = 3; case 2: a = 20; break; case 3: a = 2; break; case 4: a = 1; a = 0; } return a; ret .L16: break; movl $17, %eax ret .L17: movl $3, %eax } ret .L18: movl $20, %eax ret .L19: movl ret $2, %eax
- #include int main() { float Bread = 1.09, Water = 2.18, Banana = 1.00, Meat = 7.99; //Unit for bread is loaf, for water is bottle, for banana and meat are Ibs. int Bread_num=2, Water_num=3, Banana_num=2, Meat_num = 1; float Cost = Bread"Bread_num+Water*Water_num+Banana*Banana_num+Meat"Meat_num; float Grocery_tax = 0.07; Other part of this line is missing. Other part of this line is missing as well. [printf( [printf( getchar(); return O; } -----=-SCRIPT ENDS HERE ==== so we can have You have 2 loaves of bread, 3 bottles of water, 2 lbs of Banana, and 1 lbs of Meat. It is 18.71 before tax but you need to pay extra 1.31 for tax. as the output when we run it! Just type in two line, please! (You do not have to type in the whole script!)Briefly explain passing by valueL et D= { s, d, b}, E= { c, k}, G= { a, k }, U={a, b, c, d, k, s} DUE=
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