int days_from_epoch(int day, int month, int year) that computes and returns t number of days from the epoch, 1 January 19702, to the input date. For example. days_from_epoch(10, 1, 1970) returns 9 because it is nine days aw from the epoch. int day of_week(int day, int month, int year) that returns the day of the week the given input date. Days are represented by integers ranging from 0 for Sunday, to for Saturday. Note that the epoch, 1 January 1970, falls on a Thursday. Finally, void display_month(int month, int year) to print the specific month of t given year. The output should contain a header for the day of week "S MTWT F and the numbers should be right aligned under their respective day of the week. For example, the output for September 2017 is SMTW TFS 1 2 3 4 5 6 7 8 9 10 11 12 13 14 15 16 17 18 19 20 21 22 23 24 25 26 27 28 29 30 and the output for August 1965 is SM T W TFS 1 2 3 4 5 6 7 8 9 10 11 12 13 14 15 16 17 18 19 20 21 22 23 24 25 26 27 28 29 30 31 Hint: you may use the conversion specifier "%3d" to print an integer right justifi within 3 text spaces.

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3. int days_from_epoch(int day, int month, int year) that computes and returns the
number of days from the epoch, 1 January 1970², to the input date.
For example. days_from_epoch(10, 1, 1970) returns 9 because it is nine days away
from the epoch.
4. int day_of_week (int day, int month, int year) that returns the day of the week of
the given input date. Days are represented by integers ranging from 0 for Sunday, to 6
for Saturday. Note that the epoch, 1 January 1970, falls on a Thursday.
5. Finally, void display_month(int month, int year) to print the specific month of the
given year. The output should contain a header for the day of week " SMT WTF S"
and the numbers should be right aligned under their respective day of the week.
For example, the output for September 2017 is
S M T W T FS
1 2
3 4 5 6 7 8 9
10 11 12 13 14 15 16
17 18 19 20 21 22 23
24 25 26 27 28 29 30
and the output for August 1965 is
S M T W IF S
1 2 3 4 5 6 7
8 9 10 11 12 13 14
15 16 17 18 19 20 21
22 23 24 25 26 27 28
29 30 31
Hint: you may use the conversion specifier "%3d" to print an integer right justified
within 3 text spaces.
As this problem set is on functional abstraction, you should reuse these functions whenever
possible.
Transcribed Image Text:3. int days_from_epoch(int day, int month, int year) that computes and returns the number of days from the epoch, 1 January 1970², to the input date. For example. days_from_epoch(10, 1, 1970) returns 9 because it is nine days away from the epoch. 4. int day_of_week (int day, int month, int year) that returns the day of the week of the given input date. Days are represented by integers ranging from 0 for Sunday, to 6 for Saturday. Note that the epoch, 1 January 1970, falls on a Thursday. 5. Finally, void display_month(int month, int year) to print the specific month of the given year. The output should contain a header for the day of week " SMT WTF S" and the numbers should be right aligned under their respective day of the week. For example, the output for September 2017 is S M T W T FS 1 2 3 4 5 6 7 8 9 10 11 12 13 14 15 16 17 18 19 20 21 22 23 24 25 26 27 28 29 30 and the output for August 1965 is S M T W IF S 1 2 3 4 5 6 7 8 9 10 11 12 13 14 15 16 17 18 19 20 21 22 23 24 25 26 27 28 29 30 31 Hint: you may use the conversion specifier "%3d" to print an integer right justified within 3 text spaces. As this problem set is on functional abstraction, you should reuse these functions whenever possible.
Given the month and the year, you are required to print the Georgian Calendar' for that
month. For example, the calendar for the month of September 2017 is:
SM T W T FS
1 2
3 4 5 6 7 8 9
10 11 12 13 14 15 16
17 18 19 20 21 22 23
24 25 26 27 28 29 30
The solution to this problem can be rather complex, so we will use functional abstraction to
break it down into smaller parts. You are advised to implement and test each part (by defining
a suitable main function) before moving on the the next part.
You are to implement the following functions:
1. bool is leap_year(int year) to determine if a given year is leap.
Note that not all years which are multiples of 4 are leap. Centuries are not leap unless
they are multiples of 400.
2. int days_in_month(int month, int year) that takes the month (an integer from 1 to
12) and year, and returns number of days in the given month (an integer from 1 to 31).
Note that you should use the is_leap_year function to determine if February has 28 or
29 days.
'This is the calendar that we currently use.
Transcribed Image Text:Given the month and the year, you are required to print the Georgian Calendar' for that month. For example, the calendar for the month of September 2017 is: SM T W T FS 1 2 3 4 5 6 7 8 9 10 11 12 13 14 15 16 17 18 19 20 21 22 23 24 25 26 27 28 29 30 The solution to this problem can be rather complex, so we will use functional abstraction to break it down into smaller parts. You are advised to implement and test each part (by defining a suitable main function) before moving on the the next part. You are to implement the following functions: 1. bool is leap_year(int year) to determine if a given year is leap. Note that not all years which are multiples of 4 are leap. Centuries are not leap unless they are multiples of 400. 2. int days_in_month(int month, int year) that takes the month (an integer from 1 to 12) and year, and returns number of days in the given month (an integer from 1 to 31). Note that you should use the is_leap_year function to determine if February has 28 or 29 days. 'This is the calendar that we currently use.
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