Instruction: Find the following ΔH for the reaction below. 2SO2 + 2P + 5Cl2 → 2SOCl2 + 2POCl3 ΔH = ? Given: SOCl2 + H20 → SO2 + 2HCl ΔH = +10.3 KJ PCl3 + 1⁄2O2 → POCl3 ΔH = -325.7 KJ P + 3/2 Cl2 → PCl3 ΔH = -306.7 KJ 4HCl + O2 → 2Cl2 + 2H2O ΔH = -202.6 KJ
Instruction: Find the following ΔH for the reaction below. 2SO2 + 2P + 5Cl2 → 2SOCl2 + 2POCl3 ΔH = ? Given: SOCl2 + H20 → SO2 + 2HCl ΔH = +10.3 KJ PCl3 + 1⁄2O2 → POCl3 ΔH = -325.7 KJ P + 3/2 Cl2 → PCl3 ΔH = -306.7 KJ 4HCl + O2 → 2Cl2 + 2H2O ΔH = -202.6 KJ
Living By Chemistry: First Edition Textbook
1st Edition
ISBN:9781559539418
Author:Angelica Stacy
Publisher:Angelica Stacy
ChapterU5: Fire: Energy , Thermodynamics, And Oxidation-reduction
SectionU5.19: Current Events: Electrochemical Cell
Problem 6E
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Instruction: Find the following ΔH for the reaction below.
2SO2 + 2P + 5Cl2 → 2SOCl2 + 2POCl3 ΔH = ?
Given:
SOCl2 + H20 → SO2 + 2HCl ΔH = +10.3 KJ
PCl3 + 1⁄2O2 → POCl3 ΔH = -325.7 KJ
P + 3/2 Cl2 → PCl3 ΔH = -306.7 KJ
4HCl + O2 → 2Cl2 + 2H2O ΔH = -202.6 KJ
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