#include int main() { } int a, b, c, i=0; for (c = 0; c < 7; c++) { } for(b = 0; b < c; b+) { } for(a = 0; a < b; a++) { } return 0; printf("%d\n", i++); ) What is the final value of i in the code
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- void main (void) { char result = a; for (char i = { 10; i > 5; i = i-1) result = result + i; } // point B } Consider the code above. What is the decimal value of "result" at "point B" if the variable "a" is initially 59?#include <stdio.h>int main(){int d;int s[20],i, r, p, lg=0,m;char c;printf("Enter number of salesman(max 20): ");scanf("%d", &d);for(i=0; i<d; i++){ printf("\n salesman %d sales: ");scanf("%d", &s[i]);}for(i=0; i<d; i++){for(r=i+1; j<d; r++){if(s[i] > s[r]){p= s[i];s[i] = s[r];s[j] = p;}}}printf("\nsalesman lowest to highest: ");for(i=0; i<d; i++){printf("%d\t", s[i]);}for(i=0;i<m;i++){printf("\n highest sales: %d ",lg);if(lg<=s[i])lg=s[i];break;}getch();} >>> the upper part output should be like this enter number of salesman (max 20): 5 salesman 1 500 salesman 2 300 salesman 3 1000 salesman 4 200 salesman 5 1000 in the lower part the lowest to highest the output should become like this salesman 4 200 salesman 2 300 salesman 1 500 salesman 3 1000 salesman 5 1000 highest total sales : 2000#include using namespace std; const int y = 1; int main () { int static y = 2; int i = 3, j = 4, m = 5, n = 6; %3D int a = [] (int x, int i = 1) { return x * i; } (y, 3) ; %3D int b = [=] (int x) { return [=] (int b) { return b + j; } (x) % 7; } (a); int c = [=] (int x) mutable ->int { m = 6; return [6] (int j) mutable { y = a * b; return y / j; } (x) -m; } (b) ; cout << a << endl; cout << b << endl; cout << c << endl; cout << m << endl; cout << y < endl; return 0; This program outputs 5 lines. What are they? Please explain your work and your answer.
- CFG: Example 1 • Draw the CFG for the following code: int f(int n){ } int m = n* n; if (n < 0) else return 0; return m;Void Do1 (int: &, a. int &b) { a = 5; a = a + b; b = a + 2; } Int main() { Int x = 10; Do1 (x,x); Cout << x << endl; } The output of this program is#include <stdio.h>void cubeByReference( int *nPtr ); // function prototypeint main( void ){ int number = 5; // initialize number printf("The original value of number is %d", number ); // pass address of number to cubeByReference cubeByReference( &number ); printf("\nThe new value of number is %d\n", number );} // end main void cubeByReference( int *nPtr ){ *nPtr = *nPtr* *nPtr* *nPtr;} passing argument by reference - We modify the code above 1- define a second argument (example "int number2 = 9") and a pointer to it 2- define a second function (addByReference) that adds number2 to number - passing both arguments by reference 3- print-out the result (that is in number) Upload the output and .c codeint f(int &k){k++;return k * 2;}int main(){int i = 1, j = -1;int a, b, c;a = f(i) + i/2;b = j + f(j) + f(j);c = 2 * f(j);return 0;} What are the values of a, b and c id the operands in the expressions are evaluated from left to right and then what are the values when its evaluated right to left?#include <stdio.h>int main(){int d;int s[20],i, j, p, lg=0,m,t=0;char c;printf("Enter number of sale: ");scanf("%d", &d);for(i=0; i<d; i++){ printf("\n sales %d sales: ",i+1);scanf("%d", &s[i]);}for(i=0; i<d; i++){for(j=i+1; j<d; j++){if(s[i] > s[j]){p= s[i];s[i] = s[j];s[j] = p;}}}printf("\n sales lowest to highest: ");for(i=0; i<d; i++){printf("\nsales %d ", s[i]);}printf("\n highest: %d ",t);getch();} it should be: highest : 2000#include <stdio.h> int main(){ int M; printf("Enter the number of chairs you want to enter:\n"); scanf("%d", &M); double price[M]; double sum = 0.0; int i=0; while(i < M) { printf("Enter price of chair #%d: ",(i+1)); scanf("%lf", &price[i]); if(price[i] < 1003) { price[i] = price[i] - price[i] * 0.10; sum = sum + price[i]; } else if(price[i] >= 1003 && price[i] <= 2006) price[i] = price[i] - price[i] * 0.15; else if(price[i] > 2006) price[i] = price[i] - price[i] * 0.20; printf("Price of chair #%d after discount is %.3lf\n", (i+1), price[i]); i++; } printf("\n\nTotal price after discount of all chairs which got a discount of 10%% is "); printf("%.3lf", sum); int N = 2; printf("\n\nN is equal to the sum of My EUI ID(1+1) = 2"); double p[N]; printf("\nEnter price of %d desks: ",…int sum = 0; for (int i 0; i < 5; i++){ sum += i; } cout << sum;be recor #include #include minutes #include limit on int func(int, int, int, int); main(){ srand(time(NULL)); int a, b, c, fNum; printf("Choose three different numbers between 0-39:"); scanf ("%d%d%d", &a, &b, &c); fNum = func (a, b, c, 25); printf("\nThe result: %d", fNum); } int func (int ul, int u2, int u3, int iter){ srand (time (NULL)); int n1=0, i=0, count=0; for (;iSEE MORE QUESTIONSRecommended textbooks for youDatabase System ConceptsComputer ScienceISBN:9780078022159Author:Abraham Silberschatz Professor, Henry F. Korth, S. SudarshanPublisher:McGraw-Hill Education
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