In the methane molecule, CH4, each hydrogen atom is at the corner of a regular tetrahedron with the carbon atom at the center. If one of the C-H is in the direction of A-7+7+R and an adjacent C-H bond is at the direction B-7-7-R. results to an angular bond of approximately 109° for a static frozen molecule. However, the molecule we can encounter everyday continuously vibrates and interact with the surrounding causing its bond vector to vary slightly. According to a new spectroscopy analysis, the adjacent bond vectors was found to be A = 1.05i + 0.82) + 0.83k B = 0.97i + -0.83j + -0.98k What is the angle (in degrees) between the bonds based on this new data? Note: Only 1% of error is permitted for the correct answer.

In the methane molecule, CH4, each hydrogen atom is at the corner of a regular tetrahedron with the carbon atom at the center. If one of the C-H is in the direction of A-7+7+R and an adjacent C-H bond is at the direction B-7-7-R. results to an angular bond of approximately 109° for a static frozen molecule. However, the molecule we can encounter everyday continuously vibrates and interact with the surrounding causing its bond vector to vary slightly. According to a new spectroscopy analysis, the adjacent bond vectors was found to be A = 1.05i + 0.82) + 0.83k B = 0.97i + -0.83j + -0.98k What is the angle (in degrees) between the bonds based on this new data? Note: Only 1% of error is permitted for the correct answer.

Physics for Scientists and Engineers: Foundations and Connections

1st Edition

ISBN:9781133939146

Author:Katz, Debora M.

Publisher:Katz, Debora M.

Chapter14: Static Equilibrium, Elasticity, And Fracture

Section: Chapter Questions

Problem 42PQ: A carbon nanotube is a nanometer-scale cylindrical tube composed of carbon atoms. One of its...

See similar textbooks

Similar questions

A carbon nanotube is a nanometer-scale cylindrical tube composed of carbon atoms. One of its interesting properties is a very large Youngs modulus, measured to be more than 1.000 1012 N/m2. A tensile stress of 5.3 1010 N/m2 is exerted on a particular nanotube with a Youngs modulus measured at 2.130 1012 N/m2. Assuming the nanotube obeys Hookes law, by what percentage does the atomic spacing increase?
Determine the lowest three rotational energy levels of H2.
In the methane molecule, CH4, each hydrogen atom is at the corner of a regular tetrahedron with the carbon atom at the center. If one of the C-H is in the direction of A= i-hat + j-hat + k-hat and an adjacent C-H bond is at the direction B= i-hat - j-hat - k-hat results to an angular bond of approximately 109o for a static frozen molecule. However, the molecule we can encounter everyday continuously vibrates and interact with the surrounding causing its bond vector to vary slightly. According to a new spectroscopy analysis, the adjacent bond vectors was found to be A = 0.96i + 0.87j + 0.8k B = 0.94i + -0.98j + -1.07k What is the angle (in degrees) between the bonds based on this new data?
In the methane molecule, CH4, each hydrogen atom is at the corner of a regular tetrahedron with the carbon atom at the center. If one of the C-H is in the direction of and an adjacent C-H bond is at the direction . results to an angular bond of approximately 109o for a static frozen molecule. However, the molecule we can encounter everyday continuously vibrates and interact with the surrounding causing its bond vector to vary slightly. According to a new spectroscopy analysis, the adjacent bond vectors was found to be A = 0.84i + 0.96j + 0.9k B = 0.87i + -0.94j + -1.07k What is the angle (in degrees) between the bonds based on this new data? Note: Only 1% of error is permitted for the correct answer.
In the methane molecule, CH4, each hydrogen atom is at the corner of a regular tetrahedron with the carbon atom at the center. If one of the C-H is in the direction of A= i-hat + j-hat + k-hat and an adjacent C-H bond is at the direction B= i-hat - j-hat - k-hat results to an angular bond of approximately 109o for a static frozen molecule. However, the molecule we can encounter everyday continuously vibrates and interact with the surrounding causing its bond vector to vary slightly. According to a new spectroscopy analysis, the adjacent bond vectors was found to be A = 1.09i + 1.06j + 1.02k B = 1.01i + -0.89j + -1.02k What is the angle (in degrees) between the bonds based on this new data? Note: Only 1% of error is permitted for the correct answer.
In the methane molecule, CH4, each hydrogen atom is at the corner of a regular tetrahedron with the carbon atom at the center. If one of the C-H is in the direction of and an adjacent C-H bond is at the direction . results to an angular bond of approximately 109o for a static frozen molecule. However, the molecule we can encounter everyday continuously vibrates and interact with the surrounding causing its bond vector to vary slightly. According to a new spectroscopy analysis, the adjacent bond vectors was found to be A = 0.93i + 0.91j + 1.09k B = 1.02i + -0.99j + -1.08k
In the methane molecule, CH4, each hydrogen atom is at the corner of a regular tetrahedron with the carbon atom at the center. If one of the C-H is in the direction of and an adjacent C-H bond is at the direction . results to an angular bond of approximately 109o for a static frozen molecule. However, the molecule we can encounter everyday continuously vibrates and interact with the surrounding causing its bond vector to vary slightly. According to a new spectroscopy analysis, the adjacent bond vectors was found to be A = 0.97i + 0.89j + 0.99k B = 1.02i + -1.09j + -1.05k What is the angle (in degrees) between the bonds based on this new data?
Discuss the differences between the rotational and vibrational energy levels of the deuterium (“heavy hydrogen”) molecule D2 and those of the ordinary hydrogen molecule H2. A deuterium atom has twice the mass of an ordinary hydrogen atom.
In the methane molecule, CH4, each hydrogen atom is at the corner of a regular tetrahedron with the carbon atom at the center. If one of the C-H is in the direction of
Molecular Pair Potential The vibrational properties of a diatomic molecule can often be described by Mie's pair potential 3: U(r) = C c[9₁-9] (4) where U(r) is the potential energy between the two atoms, r is the distance between the two atoms, C, o are positive constants, and λ > 6 is a constant. The case with X 12 is the Lennard-Jones potential and was covered in Lecture #2. For the purposes of this problem, assume there is a mass ‘m’ that represents the dynamical mass of the molecule. 4 TLTR: (a) Find a combination of C, m, o that has the units of frequency. (b) Derive the ratio of the equilibrium positions and of the frequencies of small oscillations for X 10, 14. Show that the units for the equilibrium position and for the frequency of the oscillations are consistent.
A diatomic molecule has 18 x 105 eV of rotational energy in the I = 7 quantum state. What is its rotational energy in the I = 0 quantum state? %3D
(a) Express the moment of inertia of an octahedral AB6 molecule in terms of its bond lengths and the masses of the B atoms. (b) Ca lcu late the rotationa l constant of 32S19F6, for which the S-F bond length is 158 pm.