In the given circuit, X, Y, Z are input variables. When the truth table of this system is drawn, in which point the xalues of Q yariable are respectively given? (Z and A axe LSB. U1 is 8x1 multiplexer integrated. Zero stop is at the far left.) U1 X0 Y X1 6 X2 X3 X4 X5 X6 X7 14 13 12 11 9 X O 74151 O 00001010 B 00010100 O 01001000 O 10000010 O 00100001
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- What will be the final value of DI after executing the following piece of code? Execute the instructions dependently one after another. CLD MOU CX,OFOH MOU AX,05678H MOU DI,01000H MOU ES, DI SUB DI, DI REPNZ SCASB -R AX-0000 DS-073F 073F:0100 0000 D 1000:0 F 1000:0000 92 00 14 12 54 56 44 78-AD 56 78 FO 00 00 00 00 BX-0000 CX-0000 DX-0000 SP-00FD ES-1000 SS%3073F CS=073F BP-0000 SI=0000 DI=0000 IP-0100 NU UP EI PL NZ NA PO NC ADD IBX SI1,AL DS:0000 CD TUDX.Ux..... .... Notes: 1- Use the DEBUG window to answer this question (values shown are prior to execution and in hexadecimal 2- Write down the final value of DI as four hexadecimal digits without any additional characters.Part 3: Decoder can be useful when we have to decode some specific numbers from their equivalent code. Figure 6 has a concept of 3 to 8 line decoder from which you have to generate output waveform from D0 to D7 with proper relationship to input. X Y Figure_6 Part 4:The data-input and data-select waveforms in Figure 7 are applied to the multiplexer. Determine the output waveform F in relation to the inputs. DO D1 D2 D3 1. SO s1 Figure_7What will be the modified form of the following codeword is odd parity scheme is used: Codeword: 0110101
- Write Arduino program that will add two bit binary numbers and calculate the sum ofboth numbers. You have two show both numbers on seven segment as well as sum of bothnumbers will also be display on seven segment.(c) The modulus of a counter is the number of unique states through which the counter will sequence. A decade counter with a count sequence of zero (0000) through nine (1001) is a BCD decade counter because its ten-state sequence produces the BCD code. [Modulus pembilang adalah keadaan nombor unik bilamana pembilang membuat bilangan. Pembilang dekad dengan urutan kiraan sifar (0000) hingga sembilan (1001) ialah pembilang dekad BCD kerana jujukan sepuluh keadaannya menghasilkan kod BCD.] (i) (ii) Derive the state transition table. [Terbitkan jadual transisi keadaan.] With the aid of k-map, design the decade counter by using JK flip-flop. [Dengan bantuan pemetaan-k, rekabentuk pembilang dekad menggunakan JK flip-flop.]Perform the following conversion : A) converting (756.603)8 to hex b) converting A0F9.0EB to decimal C)(1001010)10 to gray D)(163.875)10 to binary E) 0110BCD to excess-3
- Answer the following Hexadecimal to decimal conversion problem: Convert the HEX NUMBER 3480. F712 to decimal number ( show steps in paper , scan and submit along with other answers) Decimal number =5) -31 is represented as a sign Binary number ( using Sign-magnitude form ) equal to (A) 00011111 (B) 10101001 (C) 01110010 (D) 00101101Adocs.google.com is a logic switch that select information from one of the input line and directs it to a single line Encoder Decoder Adder Multiplexer Binary to octal can be implemented used 3-8 De-Multiplexer Multiplexer Decoder Encoder System base 12 include numbers from ... to .... 1-B 1-C 1-12 1-11 ۹:۰۳ F
- procedure to the instructor. 6. Convert (-00101001.0011)2 to its equivalent octal and hexadecimal representation. Show all calculation procedure to the instructor.In the following circuit, X and Y values are connected to the Multiplexer inputs. Decimal values of X and Y are given as follows: X= - 2 Y= - 12 Note that both X and Y have negative values and they are represented in TYPE 2 representation, where Type 1:One's complement Type 2: Two's complement Type 3: Signed Magnitude a) Find 4-bit input values X3 X2 X1 X0 and Y3 Y2 Y1 Y0. b) Find the boolean expression for the function F2 in terms of variables A, B, C, D. c) Simplify the function you found in part b) using the karnaugh map method. Do not forget to write down the decimal value of X, Y and the representation type in your solution. |Cin хо 10 YO 10 A S F1 11 4:1 11 4:1 X1 Y1 X2 12 Mих Y 12 Mux Cout F2 Y2 • B X3 13 Y3 13 FULL si so si so ADDER А В C DA 32 bit comparator .... Please mark all answersthat are correct (at least one is correct).Is a combinational circuit ARequires only AND and OR gates to be implemented BIs a sequential circuit CCan be implemented using two 16-1 multiplexers DWith minor modifications can be transformed into a shift register E. solve this question in great detail explaining every single bit of info as i'm a complete beginner and i need to understand how to solve questions of this type. also provide small examples of how the solution would differ if the question was slightly altered