In the figure, the block of mass 2.00 kg accelerates down the inclined plane. The coefficient of kinetic friction is 0.200 and angle of the inclined plane is 30.0°. What is the acceleration of the block? normal force N friction force f mg sine mg cose mg O 3.05 m/s2 O 5.05 m/s? O 2.05 m/s? O 4.05 m/s?
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- A push of magnitude P acts on a box of weight W as shown in the figure. The push is directed at an angle 0 below the horizontal, and the box remains a rest. The box rests on a horizontal surface that has some friction with the box. The normal force on the box due to the floor is equal to: O W + P cos 0. O W + P sin 0. OW-P sin 0. O W + P. O W. W 0 PA constant applied force ?p of 15.0 N pushes a box with a mass ?=7.00 kg a distance x=15.0 m across a level floor. The coefficient of kinetic friction between the box and the floor is 0.150. Assuming that the box starts from rest, what is the final velocity ?f of the box at the 15.0 m point? If there were no friction between the box and the floor, what applied force Fnew would give the box the same final velocity?Consider the figure shown in the following figure. You are loweringtwo boxes, one on top of the other, down a ramp by pulling on a ropeparallel to the surface of the ramp. Both blocks move with constantvelocity of 10.0 [m/s]. The coefficient of kinetic friction between theramp and the lower box is 0.555 and the coefficient of static frictionbetween the two boxes is 0.750. A. Draw the Free-Body diagram of both blocks. Set the ?-axis parallel to the ramp. B. Write Newton’s 2nd law along the ? and ? directions for both blocks considering their state of motion (accelerations). C. What are the magnitude and direction of the frictional force on the upper box? D. What is the magnitude of the applied force? E. Determine the angle at which the top block will start to slide down the bottom block.
- Consider the figure shown in the following figure. You are loweringtwo boxes, one on top of the other, down a ramp by pulling on a ropeparallel to the surface of the ramp. Both blocks move with constantvelocity of 10.0 [m/s]. The coefficient of kinetic friction between theramp and the lower box is 0.555 and the coefficient of static frictionbetween the two boxes is 0.750. A. Draw the Free-Body diagram of both blocks. Set the ?-axis parallel to the ramp. B. Write Newton’s 2nd law along the ? and ? directions for both blocks considering their state ofmotion (accelerations). C. What are the magnitude and direction of the frictional force on the upper box? D. What is the magnitude of the applied force? E. Determine the angle at which the top block will start to slide down the bottom block.Timmy is done placing his things in a big box and ready to transfer to his new condo unit. The movers arrived and uses a wooden ramp with an elevation of 24.6° from the horizontal to load his things to the truck. If the box has a mass of 45.7kg and has a value of coefficient static friction is 0.936. How much force is required for the delivery man to overcome the static friction? O 568.16 N O 385.14 N O 381.54 N O No answer O 586.16 NA 98N force is needed to push a 45kg box across the wooden floor. What is the value of the coefficient of static friction across the floor and the box? O 0.212 O 0.222 O No answer O 0.122 O 0.012
- I 00LLJ408 - Go.. Question Info and Solutions Blocks A and B of mass 5 kg and 10 kg respectively are placed on a Smooth inclined plane of Inclination 30, as shown. Block A and B are subjected to forces 5 N And 50 N respectively along the incline, as shown. The coefficient of friction between A andBis 0.50 find the frictional force between A and B in N is: (g= 10 ms SOH 300 Options Solution Fs=Static frictional force umg cos 30 (0.5) (5) (10) cos 30 21.6 N Let a be the acceleration of both the blocks along 5.27 PMThe force needed to get a block moving and to just barely keep it moving were used to calculate the coefficient of static friction and the coefficient of kinetic friction for the block. Which values are most likely the correct ones for this block? O .35 for coefficient of static friction and .35 for coefficient of kinetic friction 25 for coefficient of static friction and .35 for coefficient of kinetic friction 35 for coefficient of static friction and .25 for coefficient of kinetic friction 25 for coefficient of static friction and .25 for coefficient of kinetic frictionA hand tractor of mass 1000kg is attached by means of a horizontal, massless chain to a log whose mass is 400kg. The tension in the chain is 2000N, and the backward force of friction exerted by the ground on the log is 800N. How far will the log move in 3s, starting from rest? ANS. 3m/s², 13.5m.
- A constant applied force Fp of 15.0 N pushes a box with a mass m = 8.00 kg a distance x = 15.0 m across a level floor. The coefficient of kinetic friction between the box and the floor is 0.150. Fp m Assuming that the box starts from rest, what is the final velocity of of the box at the 15.0 m point? If there were no friction between the box and the floor, what applied force Fnew would give the box the same final velocity? x m/s Uf = Fnew = NA rope pulls on the lower block in the figure with a tension force of 20 N. The coefficient of kinetic friction between the lower block and the surface is 0.16. The coefficient of kinetic friction between the lower block and the upper block is also 0.16. The pulley has no appreciable mass or friction. What is the acceleration of the 2.0 kg block?Due to a jaw injury, a patient must wear a strap that produces a net upward force of 5.00 N on his chin. The tension is the same throughout the strap. Q: To what tension must the strap be adjusted to provide the necessary upward force?