In the figure, bus 1 is the reference bus, V1 = 1.06 p.u and the angle is 0•. A load with active power= 100 MW and reactive power = 50 Mvar is connected to bus 2. The line impedance is z12 =0.12 + j0.16 p.u on a base of 100 MVA Start with an initial estimate of |V2|®) = 1.0 p.u and 82) = 0•. Find |V2| (4) (one iteration). 2 212 = 0.12 + j0.16 100 MW Vị = i.020° ++ 50 Mvar |V2| (1) = 0.4 p.u. O b. |v2| (1) = 0.5 p.u. O C. Įv2| (1) = 0.7 p.u. O d. Įv2| (1) = 0.8 p.u. Oe. |V2| (1) = 0.6 p.u.

Power System Analysis and Design (MindTap Course List)
6th Edition
ISBN:9781305632134
Author:J. Duncan Glover, Thomas Overbye, Mulukutla S. Sarma
Publisher:J. Duncan Glover, Thomas Overbye, Mulukutla S. Sarma
Chapter6: Power Flows
Section: Chapter Questions
Problem 6.61P
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In the figure, bus 1 is the reference bus, V1 = 1.06 p.u and the angle is 0.. A load with active power= 100
MW and reactive power = 50 Mvar is connected to bus 2. The line impedance is z12 = 0.12 + j0.16 p.u on
a base of 100 MVA. Start with an initial estimate of |V2|0) = 1.0 p.u and 820) = 0•. Find |V2| () (one
iteration).
100 MW
212 = 0.12 + j0.16
++ 50 Mvar
Vị = 1.0/0°
О а.
|V2| (1) = 0.4 p.u.
Ob.
|V2| (1) = 0.5 p.u.
Oc.
|V2| (1) = 0.7 p.u.
d.
(1) = 0.8 p.u.
е.
|V2|
(1) = 0.6 p.u.
Transcribed Image Text:In the figure, bus 1 is the reference bus, V1 = 1.06 p.u and the angle is 0.. A load with active power= 100 MW and reactive power = 50 Mvar is connected to bus 2. The line impedance is z12 = 0.12 + j0.16 p.u on a base of 100 MVA. Start with an initial estimate of |V2|0) = 1.0 p.u and 820) = 0•. Find |V2| () (one iteration). 100 MW 212 = 0.12 + j0.16 ++ 50 Mvar Vị = 1.0/0° О а. |V2| (1) = 0.4 p.u. Ob. |V2| (1) = 0.5 p.u. Oc. |V2| (1) = 0.7 p.u. d. (1) = 0.8 p.u. е. |V2| (1) = 0.6 p.u.
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