In the figure below, set-up the integral expression when the area bound by the functions y- y-4 4 and is revolved around the -4 axis using the method of disks. (0.25, 4) y1/x (4, 0.25) Ov-- ( -4) dv
In the figure below, set-up the integral expression when the area bound by the functions y- y-4 4 and is revolved around the -4 axis using the method of disks. (0.25, 4) y1/x (4, 0.25) Ov-- ( -4) dv
Algebra & Trigonometry with Analytic Geometry
13th Edition
ISBN:9781133382119
Author:Swokowski
Publisher:Swokowski
Chapter3: Functions And Graphs
Section3.4: Definition Of Function
Problem 52E
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Transcribed Image Text:Question 8
In the figure below, set-up the integral expression when the area bound by the functions y =. y=4
=4 and is revolved around the z = 4 axis using the method of disks.
(0.25, 4)
y1/x
(4, 0.25)
Ov-a (4-)*
Ov=-f ( -4)
Ov--(1- })'
Ov- (4- ;) dv
Transcribed Image Text:Question 7
In the figure below, set-up the integral expression when the area bound by the functions y= y =4
3=2 and s=4 is revolved around the =d axis using the method of disks.
(0.25, 4)
(4, 4)
y = 4
(2, 4)
y 1/x
(2, 0.5)
(4, 0.25)
-1
dy +
Ov=T
V = 2r
dy +
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