In the fig. shown, compute the ff : (11-13) the tension in cable BD 7.5 rt To = (14-15) the components of the support 10 re At C. Ch = Cv = 5 rt 1000 lb 12.5 ft
Q: 750 N 150 mm 250 mm - 500 mm· B 450 N h 400 mm C D
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Q: D 7.5 ft B 10 ft 5 ft 12.5 1000 lb
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Q: In the fig. shown, compute the ff : D (11-13) the tension in cable BD 7.5 ft TBD = в (14-15) the…
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Q: Ok A 30k 20 k 20 k 20 k 30k 30 ft- 30 ft 30 ft- 30 ft
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Q: G H I 20.0 kN E A 15.0 kN B 15.0 kN -2.00 m - -2.00 m - 2.00 m -2.00 m 40.0 kN NY O'09 40.0kN
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- Help Save & Exit Check Required information A rope connecting points A and B supports the force Fshown in the figure. Write expressions using Cartesian vector representation for the following. Take L= 8 ft and F= 12 lb. NOTE: This is a multi-part question. Once an answer is submitted, you will be unable to return to this part. B 30° F T AB : the position vector from A to B. TAB of 17 Next > < Prev 6. 9. 41S00 Ib In the fig. shown, compute the ff: (16-18) the resultant using cosine law (force polygon) 60 R = 35 (19-20) the angle of the R measured 500 lb cW from the x- axis.Assign the values of shear force and bending moment to the image bar as a function of the x coordinate. q=20kN/m F=14kN M=12kNm L1=1.2m L2=1.4m L3=1.3m L4=1.5m Minimum value of shear force: Qmin = Maximum value of shear force: Qmax= Use units (kN,m), Do not round the invoices in the intermediate stages, but only the final answer!
- Q) A simplified model as shown in figure below of a planar robotic arm. You may assume that each segment has length 1.5 m, and the applied force is 250 N. 01 = 35 degree and 02 = 03 = 20 degree. Calculate the %3D moment that the force, F, exerts .about the point A F A. M = -1042 O M = -1055 M = -1046 M = -1050 OI. Solve the following problems completely: Show your complete solution and draw the graph. 1. Locate, and find the magnitude and the position of the resultant R at point A of the forces acting on the Fink Truss shown in the figure. Find the couple at point B. Given Figure: 250N 30⁰ 350N 8m 60% 4m 450N 2100N 8m 8m 60⁰ 8m 60% 350N 4m 60⁰ 30⁰ 8m 250N B6 in 60° 20 in Statics Instructor A vertical force of P = 100 lb is required to remove the nail at C from the board. Determine the magnitude of the moment about B exerted by the 100 lb vertical force. Draw a free body diagram for the system. Then, use what you know about moments to solve for Mp What is the magnitude of the moment at point B due to P if P = 100 lb and 9 = 10"? Round to the nearest whole number. Enter a response then click Submit below lb in
- Required information A rope connecting points A and B supports the force F shown in the figure. Write expressions using Cartesian vector representation for the following. Take L = 8 ft and F= 12 lb. NOTE: This is a multi-part question. Once an answer is submitted, you will be unable to return to this part. y 30° es ÜAB : the unit vector in the direction from A to B. ûAB =The figure below shows a steel structure made up of two pre-assembled segments that are hoisted by a mobile crane using a bespoke lifting frame. Each cable must withstand loads of FAB = FAC = FAD = FAE = 4000 kN. You must provide an accurate answer in scientific standard form with one decimal place only. In cartesian vector and in scalar form, compute the rAB, rAC, TAD & rAE length. 14 m 6m 6 m в 3 m 3 m X3) A point mass is attached to one end of a beam levered against a spike which acts as the pivot. The point mass weighs 250N and the beam has a uniform mass of 10kg and is 8m long. Parts a and b Part c Fapplied 3 of 6mov 1m 8m Krist 0 = 60° Scale 250 N Scale a. If a scale placed beneath the point mass reads 250N, what is the magnitude and direction for the force at the pivot point? Direction: North, 90° from x-axis Magnitude to k* 250N = 2500 N b. For the same scenario, how far must the pivot point be located relative to the left edge of the beam? (Hint, both the boxes weight and the force from the scale act at the farthest right edge of the beam.) www.acta 0672nos onl c. The pivot is then moved to be 6m from the left edge of the beam which now makes a 60 angle with the floor. How much downward force would be needed at the left-most edge of the beam to reduce the reading on the scale to zero? (Hint: the beam is still in static eq. when the scale reads zero.)
- Engineering Analysis ENGR 1022. Vectors Homework #3 1. Compute the dot product for the following two vectors. A=51+3) and = 31-10) 2. Compute the cross product for the following vectors? C= 61-9) and 5 =91-4k 3. What is the force in cable AC? See diagram below. B 500 lb 4. The magnitude of torque equals force times distance. The vector form is r=7x F. F is the force vector and F is the position vector. You are pushing on a merry-go-round with a radius of 5 ft with a force of 40 lbs. What is the torque vector value? The z axis is pointing out of the sheet of paper. See diagram below. y 5. Show that vectors 7,7, and F in problem 4 are all perpendicular to each other. University of Arkans Fot S5210 Grand Avenue PO, Box 3649 Fort South, Arkama 72933-3649-475-753-70008:30 Test 3.pdf F1 F2 a CF3 A b a F4 D Consider the following values: - F5 a = 12 m; b = 10 m; c = 10 m; d = 8 m; F1 = 6 kN; F2 = 7 kN; F3 = 8 kN; F4 = 9 kN; F5 = 10 kN; a = 30°, 0= 45° , B = 60° 1] What is the resultant moment of the five forces acting on the rod about point A? a) - 111.6 kN.m b) 112.6 kN.m e) - 184.6 kN.m d) - 109.6 kN.m e) - 104.1 kN.m 0 None of them 21 What is the resultant moment of the five forces acting on the rod about point B? a) -95.8 KN.m b) 42.7 kN.m c) 80.9 kN.m d) 10.9 kN.m e) 51.8 kN.m ) None of them 31 What is the resultant moment of the five forces acting on the rod about point C? b) - 21.1 kN.m e) 17.4 kN.m d) - 16.5 kN.m e) 15.6 kN.m ) None of them a) 32.6 kN.m 4] What is the resultant moment of the five forces acting on the rod about point D? a) 37.6 kN.m b) 73.8 kN.m c) 71.6 kN.m d) 52.1 kN.m e) 21.1 kN.m ) None of them 5] What is the moment of the force F2 about point E? a) 90.7 kN.m b) - 88.1 kN.m c) 54.6 kN.m d) 103.1 kN.m e) 100.7 kN.m ) None…The following diagram corresponds to questions 1 to 3. A beam rests on two sharp edges as shown on the image. The beam has a length of 7,50 m and a mass of 4,25 kg. Object 1 has a mass of 1,50 kg; object 2 has a mass of 2,35 kg. Point P is 0,50 m form the center of the beam. CG 1. How much is the torque done by object 1 around point P? A. 55,2 N*m B. 7,36 N*m C. 62,5 N*m D. Object 1 doesn't exert a torque. 2. How much is the torque done by the force of gravity of the beam around point P? A. 20,8 N*m N-m ך177 .B C. 156 N*m D. 313 N*m 3. If you needed to cancel the nomal forces of the two objects, where you should place object 2? The axis of rotation is point P. A. 3,30 m from point B. 9,18 m from point P C. 5,69 m from point P D. 3,62 m from point P