In Peter Jackson's adaptation of The Two Towers, the wizard Gandalf falls from the Bridge of Khazad-dûm for a total screen time of 71 seconds. Darren wanted to calculate the maximum height the fall could have been and running the numbers concluded that it could be at most 4.94 km from the bridge to the heart of the mountain below.   Is Darren's conclusion a fair estimation of the total fall distance?

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In Peter Jackson's adaptation of The Two Towers, the wizard Gandalf falls from the Bridge of Khazad-dûm for a total screen time of 71 seconds. Darren wanted to calculate the maximum height the fall could have been and running the numbers concluded that it could be at most 4.94 km from the bridge to the heart of the mountain below.

 

Is Darren's conclusion a fair estimation of the total fall distance?

 

Be sure to:

*State your claim of agreeing or disagreeing with 4.94 km being a reasonable height for the fall.

*Gather evidence from your own calculations, observations from the film.

*Connect your evidence to your claim by reasoning why it supports your claim. Any evidence you share should be directly linked with your reasoning to why or why not 4.94 km is a reasonable estimate for the falling distance.

Conclusions (what can we claim, what can
provide as evidence, what is the reasoning?)
Claim
The train will NOT stop in time.
Evidence:
Reasoning
m/s² and only has 300 meters to stop Will it stop in time?
dax
Givens:
v₁ = 60 m/s
V₁ = ON
a=-345²
1
0² = 50² +2(3)x
0 = 2560 -4*
3x 2000
X = 625A
16
*****
With the given values, the evidence of the calculation
of the stopping distance was found to be 625m. That is
greater than the 300m of the car's location, so the train
can not stop in time.
Transcribed Image Text:Conclusions (what can we claim, what can provide as evidence, what is the reasoning?) Claim The train will NOT stop in time. Evidence: Reasoning m/s² and only has 300 meters to stop Will it stop in time? dax Givens: v₁ = 60 m/s V₁ = ON a=-345² 1 0² = 50² +2(3)x 0 = 2560 -4* 3x 2000 X = 625A 16 ***** With the given values, the evidence of the calculation of the stopping distance was found to be 625m. That is greater than the 300m of the car's location, so the train can not stop in time.
A train is traveling at 50 m/s and needs to come to a stop before it hits
an empty car abandoned on the tracks. It can decelerate at a rate of 2
m/s² and only has 300 meters to stop. Will it stop in time?
= V
dax
Givens:
solve for the stopping distance
X and compare that to the 300 m
t=
V₁ =
50m/s
V₁ = 0 M/s
a = -a m/s²
?
24
X
0² = 50² +2(-2)×
2560 -4X
O
+4x
+ 4x
4x = 2500
U
X = 625m
a =
(vp - v₁)
22f = 12₁ + at
v² = v² + 2ax
1
x = 1₁t+ = at ²
x=(²²+ 2/²) ₁
2
Transcribed Image Text:A train is traveling at 50 m/s and needs to come to a stop before it hits an empty car abandoned on the tracks. It can decelerate at a rate of 2 m/s² and only has 300 meters to stop. Will it stop in time? = V dax Givens: solve for the stopping distance X and compare that to the 300 m t= V₁ = 50m/s V₁ = 0 M/s a = -a m/s² ? 24 X 0² = 50² +2(-2)× 2560 -4X O +4x + 4x 4x = 2500 U X = 625m a = (vp - v₁) 22f = 12₁ + at v² = v² + 2ax 1 x = 1₁t+ = at ² x=(²²+ 2/²) ₁ 2
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