In Part I of the experiment, you will prepare 5 solutions according to the chart below. Notice that the final volume of each solution is 50 mL. 0.200 M Fe(NO3)3 0.0020 M SCN™ H20 Beaker number (mL) (mL) (mL) 1 (blank) 5.0 0.0 45.0 2 5.0 5.0 40.0 3 5.0 4.0 41.0 4 5.0 3.0 42.0 5 5.0 2.0 43.0 For the solutions that you will prepare in Part I, calculate the [FeSCN²]. Assume that all of the SCN ions react. In Part I of the experiment, mol of SCN=mol of FeSCN2+. Thus, the calculation of [FeSCN2] is: mol FeSCN2 + L of total solution. Or, you can use M₁V₁= M₂V₂. Show at least one sample calculation.
In Part I of the experiment, you will prepare 5 solutions according to the chart below. Notice that the final volume of each solution is 50 mL. 0.200 M Fe(NO3)3 0.0020 M SCN™ H20 Beaker number (mL) (mL) (mL) 1 (blank) 5.0 0.0 45.0 2 5.0 5.0 40.0 3 5.0 4.0 41.0 4 5.0 3.0 42.0 5 5.0 2.0 43.0 For the solutions that you will prepare in Part I, calculate the [FeSCN²]. Assume that all of the SCN ions react. In Part I of the experiment, mol of SCN=mol of FeSCN2+. Thus, the calculation of [FeSCN2] is: mol FeSCN2 + L of total solution. Or, you can use M₁V₁= M₂V₂. Show at least one sample calculation.
Chemistry for Engineering Students
4th Edition
ISBN:9781337398909
Author:Lawrence S. Brown, Tom Holme
Publisher:Lawrence S. Brown, Tom Holme
Chapter12: Chemical Equilibrium
Section: Chapter Questions
Problem 12.37PAE: Again the experiment in Exercise 12.33 was redesigned. This time, 0.15 mol each of N, and O2 was...
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