In order to solve for the time, t, in two steps you must: Step One Add the same expression to each side of the equation to leave the term that includes the variable by itself on the right- hand side of the expression: (Be sure that the answer field changes from light yellow to dark yellow before releasing your answer.) + In[A] = –kt + In [A], Drag and drop your selection from the following list to complete the answer: 1 1 - In[Ao] In[Ao] In[Ao] In[Ao]

Chemistry by OpenStax (2015-05-04)
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Author:Klaus Theopold, Richard H Langley, Paul Flowers, William R. Robinson, Mark Blaser
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Chapter12: Kinetics
Section: Chapter Questions
Problem 65E: The hydrolysis of the sugar sucrose to the sugars glucose and fructose, C12H22O11+H2OC6H12O6+C6H12O6...
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The concentration for a first-order reaction is given by the equation:
In[A] = -kt + In [A],
Where:
[A] = concentration of reactant A
[A]o = initial concentration of reactant A
k
= rate constant
t = time
In order to solve for the time, t, in two steps you must:
Step One
Add the same expression to each side of the equation to leave the term that includes the variable by itself on the right-
hand side of the expression:
(Be sure that the answer field changes from light yellow to dark yellow before releasing your answer.)
+ In[A] =
-kt + In [A]o
Drag and drop your selection from the following list to complete the answer:
1
1
– In[Ao]
In[Ao]
In[Ao]
-
In[Ao]
Transcribed Image Text:The concentration for a first-order reaction is given by the equation: In[A] = -kt + In [A], Where: [A] = concentration of reactant A [A]o = initial concentration of reactant A k = rate constant t = time In order to solve for the time, t, in two steps you must: Step One Add the same expression to each side of the equation to leave the term that includes the variable by itself on the right- hand side of the expression: (Be sure that the answer field changes from light yellow to dark yellow before releasing your answer.) + In[A] = -kt + In [A]o Drag and drop your selection from the following list to complete the answer: 1 1 – In[Ao] In[Ao] In[Ao] - In[Ao]
Expert Solution
Explanation

ln [A] = -kt + ln [A]o 

Adding -ln[A]o on both sides,

ln[A] - ln[A]o = -kt + ln[A]o - ln[A]o 

1k x lnAoA = t 

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