In order to set rates, an insurance company is trying to estimate the number of sick days that full time workers at an auto repair shop take per year. A previous study indicated that the standard deviation was  3.3  days. How large a sample must be selected if the company wants to be  99%  confident that the true mean differs from the sample mean by no more than  1  day?     73     157     90     52

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A: The given ZSTAT is -2.03 and level of significance is 0.05.

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A: GivenMean(μ)=23standard deviation(σ)=15sample size(n)=38

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A: given datadf=5we have to find out the p(-3.09&lt;t&lt;-2.77)=?here we use excel function for find…

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A: Formula Used: If Larger standard deviationSmaller standard deviation &gt; 2 ,then we shall  T-test…

Q: If we find a 95% confidence interval using a sample, then we can say... 95% of individuals will fall…

A: According to the given information in this question We need to identify the correct option

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A: Comment: As per the company guidelines we are supposed to answer only three subparts. Kindly repost…

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A:

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A: It is given for the distribution of the population that: μ(mean)=50σ(standard deviation)=4

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A: * solution :-    From the given information the answer is given as

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A: Hi! Thank you for the question, As per the honor code, we are allowed to answer three sub-parts at a…

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A: It is needed to find the explanatory and response variable.

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A: Given that  Population mean μ =3.2 Population standard deviation =1.5

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A: The following information has been provided: Class Frequency 20 - 22 3 23 - 25 2 26 - 28 1…

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A:

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A: Given data: Neighborhood 1 Neighborhood 2 57 32 46 47 49 41 51 57 56 43 47 50

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A: given data n = 303x = 48p^ = xn = 48303 = 0.158495% ci for pα = 1 - 0.95 = 0.05

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A: In this case, the baseline (x) is the independent variable, and the one year follow-up values (y) is…

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A: given data, assume the variable is normally distributed.μ=100σ=15If a personnel manager wishes to…

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A: Given n=100  0.10 significance level

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A: Here, the average college student drinks 12 cups of coffee a week.

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A:

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A: Givensample size(n)=30Mean(x)=60standard deviation(σ)=10confidence level=95%

Q: 3. In a normal frequency distribution of serum sodium concentrations, the mean is 141 mEq/L and the…

A: given data, normal distribution μ=141σ=3.2p(137.8&lt;X&lt;144.2)=?

Q: Joey wants to calculate his calculus grade. The teacher's policy is that the tests count 40%,…

A: Here, Marks's test average is 92, 95, 100, 90 and 92.

Q: Compare empirically Samirnov test to test the normality the power of Shapiro-Wilk test and…

A: Solution: According to the guidelines if multiple questions are asked only first question should be…

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A: given data  standard normal distribution  Z~N(0,1) area to the right of z = 0.95 Z = ?

Q: The Physicians' Health Study is a very large, randomized, double blind study designed to "test the…

A: a) The subjects were assigned into two groups.

Q: Two processes for manufacturing large roller bearings are under study. In both cases, the diameters…

A: It is given that  For sample 1: s21 = 0.235 n1 = 21   For sample 2: s22 = 0.128 n2 = 26

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A: given data  μ= 105σ = 5 n=45

Q: The average charitable contribution itemized per income tax return in a certain state is $792.…

A: Given Mean=792 Standard deviation=103